Initially, 0.740 mol of A is present in a 5.00 L solution. 2 A ( aq ) − ⇀ ↽ − 2 B ( aq ) + C ( aq ) At equilibrium, 0.200 mol of
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Answer:
10 is 2.89g/ml
11 in attachment
Explanation:
10. D=M/V
M=250G-120G=130G
V=75ML-30ML=45ML
D=130/45=2.89g/ml
