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3 years ago

6

Initially, 0.740 mol of A is present in a 5.00 L solution. 2 A ( aq ) − ⇀ ↽ − 2 B ( aq ) + C ( aq ) At equilibrium, 0.200 mol of

C is present. Calculate K.

1 answer:

drek231 [11]3 years ago

4 0

Answer:

POINTZZZ

Explanation:

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Moles of glucose = Molarity x volume solution
= 4.5 x 1.5
= 6.75 moles.

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3 years ago

19. What is sthe mass of 6.02 x 1024 atoms

alekssr [168]

The mass of magnesium in $6.02 \times 10^{24}$ atoms is 240 g.

Answer: Option A

<u>Explanation:</u>

First, we have to convert the atoms to moles of magnesium.

We know that $6.02 \times 10^{24}$ atoms are present in 1 mole of magnesium. So,

$\text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }$

$6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }$

Thus,

$Mass of M g= molar mass of M g \times No. of moles of M g$

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Thus, 240 g of Magnesium is present in $6.02 \times 10^{24}$ atoms.

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What force is the type of intermolecular force that would be present between molecules of Cl2 ?

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Cl2 is nonpolar so it has to be only London dispersion force (LDF)

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