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2 years ago

6

Initially, 0.740 mol of A is present in a 5.00 L solution. 2 A ( aq ) − ⇀ ↽ − 2 B ( aq ) + C ( aq ) At equilibrium, 0.200 mol of

C is present. Calculate K.

1 answer:

drek231 [11]2 years ago

4 0

Answer:

POINTZZZ

Explanation:

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