Question

Please help. I’m really struggling. No wrong answers please, if you don’t know it please don’t answer, I’m already failing the class.

Answer 1

Answer:

$C_{3}H_{3} O_{1}$

Explanation:

There are empirical formula calculators on the search engine that starts with G (This word is blocked by Brainly) and if you really need to use it, there's an option you can choose. However, I will try to explain this.

C = 65.4

H = 5.5

O = 29.1

We first need to divide the percentages by their molar mass.

65.4/12.01 = 5.44

5.5/1.008 = 5.46

29.1/16 = 1.8

We then need to divide these numbers by the smallest number we obtained.

1.8 is smaller than 5.46 and 5.46, so we would divide all three numbers with 1.8.

5.44/1.8 = 3

5.46/1.8 = 3

1.8/1.8 = 1

This means that there are 3 atoms of C and H and 1 atom of O, giving us the empirical formula of $C_{3}H_{3} O_{1}$.