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Mandarinka [93]
2 years ago
5

Question 1 (1 point)

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
4 0

Answer:

ok

Step-by-step explanation:

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Pia printed two maps of a walking trail. The length of the trail on the first map is 8 cm. The length of the trail on the second
Vlada [557]
Scale :

Map 1 : Actual
1 cm   :  2 km
1 cm   :  200 000 cm          | Convert 2km to 200 000cm

Answer: The scale is 1 : 200 000 

Map 1 : Actual
1 cm   :  200 000 cm 
(x8)    :   (x8)
8 cm :  1 600 000cm

1 600 000 cm = 16 km

Answer: The length of the actual trail is 16 km

Map 1 : Map 2
8cm   :   6cm
1cm    :    0.75 cm

Answer : The scale is 1 : 0.75

Map 1 : Map 2
1    :  0.075 

3mm : 0.075 x 3 = 0.225mm

4mm : 0.075 x 4 = 0.3 mm

5mm : 0.075 x 5 = 0.375 mm

Answer: The side lengths are 0.225mm, 0.3 mm and 0.375 mm

3 0
3 years ago
Why does a y-intercept not count as a zero?
Genrish500 [490]

Answer:

It only counts as a zero when the y-intercept is (0,0).

Step-by-step explanation:

The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.

7 0
3 years ago
Help me pleaseeeeeeeeeeeeeeeeeeeeeeeee
ArbitrLikvidat [17]
Eduardo is packing 12 pairs of mismatched socks for his trip.
3 0
3 years ago
Read 2 more answers
Allie sold oatmeal cookies at a stand for two days. She made 35.20 on the first day. She used 1/4 of this money to buy more supp
Tju [1.3M]
Multiply the money earned on the first day ($35.20) by 1/4.

= 35.20 * 1/4
multiply numerators

= (35.20 * 1)/4

=35.20/4
divide

= $8.80


ANSWER: $8.80 was used to buy more supplies

Hope this helps!  :)
4 0
3 years ago
Suppose that the function f is defined. , for all real numbers, as follows.
aivan3 [116]

Answer:   <em>The values of......</em>

<em>f(-5)=\frac{9}{4}\\ \\ f(-2)= -1\\ \\ f(4)=0</em>

Step-by-step explanation:

Given function is:   \left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.

For f(-5),  the value of x is -5, which is not equal to -2.

So,  f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}

For f(-2),  the value of x is -2.

So,  f(-2)= -1

For f(4),  the value of x is 4, which is not equal to -2.

So,  f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0

5 0
3 years ago
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