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olchik [2.2K]
3 years ago
6

What is being cycled??

Chemistry
1 answer:
swat323 years ago
6 0
Water is constantly being cycled between the atmosphere, the ocean and land. This cycling is a very important process that helps sustain life on Earth. As the water evaporates, vapors rise, and condense into clouds. The clouds move over land, and precipitation falls in the form of rain, ice, or snow.
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Which would be the biggest long-term benefit of building a city recycling center? A. building the new recycling building
Shkiper50 [21]

Answer:

C

Explanation:

garbage being reduced is a far more long term other than the other stupid answer choices

7 0
3 years ago
A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

4 0
3 years ago
A metal (M) forms an oxide with the formula MO. If the oxide contains 7.17 % O by mass, what is the identity of the metal?
Nataly_w [17]

The metal is lead, Pb.

One unit of the oxide contains one atom of O (16.00 u).

∴ Mass of oxide = 16.00 u O × (100 u MO/7.17 u O) = 223.15 u MO

Mass of M = mass of MO – mass of O = 223.15 u -16.00 u = 207.2 u

The only element with an atomic mass of 207.2 u is lead (Pb) and the formula of the oxide is PbO.

7 0
3 years ago
AICI3(s)+Ca 3N2(s)-AIN(S)+CaCl2(s)
disa [49]

Answer:

2AlCl3 + Ca3N2 - 2AlN+ 3CaCl2

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Use the information from the diagram to calculate the enthalpy of combustion for methane. (HELP ASAPPP!!)
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where is the diagram sisters

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