Which of the following statements is consistent with the electron configuration 1s22s22p63s23p4?

Chemistry

1 answer:

spayn [35]3 years ago

6 0

Answer:

Explanation:

When finding the element based on its electronic configuration the subscripts gives the number of electrons in the element.

In the given example total number of subscripts are 16. This means the element has 16 electrons which is equal to the atomic number of the element. hence, the element is Sulphur.

Here, s, p, d, and f are orbitals. So, as per the EC given, 3p orbital has 4 electrons in it. Hence, option (a) is correct.

Since, s, p, d, and f are orbitals and not shells, subshells. Therefore, other options are incorrect.

You might be interested in

Solutions that have more h than oh- ions are

mestny [16]

They are Acids

when acids are in water they dissociate and release H+ ions into the water

while bases release OH- ions

hope that helps

5 0

3 years ago

Read 2 more answers

What is the octet rule? What is it based on?

Nimfa-mama [501]

Answer: The octet rule is a chemical rule of thumb that reflects the observation that main group elements tend to bond in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas.

Explanation:

8 0

3 years ago

Describe the heat involved if you touch a flask containing an on-going endothermic reaction

juin [17]

The flask would feel cooler than when the reaction first started.

8 0

4 years ago

When a solution of 0.1 M Mg(NO3)2 was mixed with a limited amount of aqueous ammonia, a light white, wispy solid was observed, i

Ipatiy [6.2K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

$Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)$

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

$Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)$