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Kazeer [188]
2 years ago
14

A wave has a wavelength of 3 m and a frequency of 340 Hz. How far will the wave go in 20 s?

Physics
1 answer:
Lady bird [3.3K]2 years ago
5 0
Answer:
Velocity=wavelength X frequency
= 3X340
= 1020m/s
Velocity/speed=distance ×time
Distance =velocity/time
=1020/20
=51m
Explanation:

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What steps should be taken to increase the amount of current produce a generator​
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Answer:

The maximum potential difference or current can be increased by:

1. increasing the rate of rotation.

2. increasing the strength of the magnetic field.

3. increasing the number of turns on the coil.

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The Tesla Roadster electric car is rated at 16.8kW. How much energy does it use during a one hour drive? Answer in MJ
ASHA 777 [7]

(16.8 kW) means (16,800 joules/second)

Energy in 1 hour = (1 hour) x (16,800 J/s) x (3,600 s/hour)

Energy = (16,800 x 3,600) J

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An asteroid is on a collision course with Earth. An astronaut lands on the rock to bury explosive charges that will blow the ast
forsale [732]

Answer:

The maximum radius the asteroid can have for her to be able to leave it entirely simply by jumping straight up is approximately 1782.45 meters

Explanation:

Whereby the height the astronaut can jump on Earth = 0.500 m, we have the following kinematic equation;

v² = u² - 2·g·h

Where;

v = The final velocity

u = The initial velocity

g = The acceleration due to gravity ≈ 9.8 m/s²

h = The height she jumps

At the maximum height, h_{max} = 0.500 m, she jumps, v = 0, therefore, we have;

0² = u² - 2·g·h_{max}

u² = 2 × 9.8 × 0.5 = 9.8

u = √9.8 ≈ 3.13

u = 3.13 m/s

Her initial jumping velocity ≈ 3.13 m/s

Escape velocity, v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{r} }

Where;

M = The mass of the asteroid

G = The Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)

r = The radius of the asteroid

The average density of the Earth = 5515 kg/m³

The mass of the asteroid, M = Density × Volume = 5515 kg/m³× 4/3 × π × r³

The escape velocity, she has, v_e ≈ 3.13 m/s is therefore;

3.13 = \sqrt{\dfrac{2 \times 6.67408 \times 10^{-11} \times 5515 \times \frac{4}{3} \times \pi \times r^3}{r} } = r \times \sqrt{3.084 \times 10^{-6}}

r = \dfrac{3.13}{ \sqrt{3.084 \times 10^{-6}}} \approx 1782.45

Therefore, the maximum radius of the asteroid can have for her jumping velocity to be equal to the escape velocity for her to be able to leave it entirely simply by jumping straight up = r ≈ 1782.45 meters.

7 0
3 years ago
5. A wave with peaks separated by .34 m has a wavelength of ________________m.
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8 0
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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

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\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
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