Answer:
Explanation:
Let the normal force of the wall on the ladder be N2 and the normal force of the ground on the ladder be N1.
Horizontal forces:
[1]
Vertical forces:
[2]
Substitute [2] into [1]:
![N_2 = (u1)*[m*g - (u2)(N_2)]](https://tex.z-dn.net/?f=N_2%20%3D%20%28u1%29%2A%5Bm%2Ag%20-%20%28u2%29%28N_2%29%5D)
![N_2= \frac{(u1)m*g}{[1 + (u1)(u2)]}](https://tex.z-dn.net/?f=N_2%3D%20%5Cfrac%7B%28u1%29m%2Ag%7D%7B%5B1%20%2B%20%28u1%29%28u2%29%5D%7D)
[3]
Torques about the point where the ladder meets the ground:
![[1 + (u1)(u2) - 2(u2)(u1)]/2 [1 + (u1)(u2)]= [(u1)/[1 + (u1)(u2)]]cot\alpha](https://tex.z-dn.net/?f=%5B1%20%2B%20%28u1%29%28u2%29%20-%202%28u2%29%28u1%29%5D%2F2%20%5B1%20%2B%20%28u1%29%28u2%29%5D%3D%20%5B%28u1%29%2F%5B1%20%2B%20%28u1%29%28u2%29%5D%5Dcot%5Calpha)
tanα = 
The number of oscillations of the toy in a second is 1.25.
<h3>What is frequency?</h3>
- This is the number of complete oscillation of an object is a given period.
The given parameter:
- Frequency of the toy, F = 1.25 Hz
The frequency of an object is calculated as follows;
where;
- n is the number of oscillations
- t is the time of motion
The number of oscillations of the toy in a second is calculated as follows;
Learn more about frequency here: brainly.com/question/10728818
Here, we are required to determine the reaction of the power given to a circuit supplied with a constant voltage as the distance of the circuit decreases.
- In a circuit supposed with a <em>constant voltage</em>, as the resistance of the circuit decreases, the power given to the circuit Increases as evident in the formular: P = V²/R
The power given to a circuit is given by the formula;
Power, P = V × I
where, V = voltage supplied
and I = Current through the circuit.
However, from Ohm's law;
V = I × R
In essence, I = V/R
By substituting, I = V/R into the equation P = V × I
Therefore, we have;
P = V²/R.
Ultimately, if the circuit is supplied with a constant voltage, As the resistance of the circuit decreases, the power given to the circuit Increases.
Read more:
brainly.com/question/16488641
Answer:
speed is affected by the medium in wich the wave travels.
Explanation:
The speed of a wave is affected when traveling in different medium, depending on the medium in which the wave travels it can go faster or slower, or not even be able to travel in that medium.
For light waves, the denser the medium through which the wave travels, the slower it will go through it, as there is more resistance to the light particles.
And in waves like sound, which instead of particles is a vibration or disturbance in the medium, they travel faster in denser mediums such as metal, because the disturbance is transmitted more efficiently thanks to how close together that the particles are in the metal, This is why sound does not travel in a vacuum; there are not even particles to transmit the vibration.
