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nataly862011 [7]

3 years ago

14

How fast is the world's fastest train? name the train and what country is it in

1 answer:

SSSSS [86.1K]3 years ago

5 0

Answer:

SCMaglev, Located in Japan

Explanation:

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The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is

Ugo [173]

Answer:

A

Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.

Explanation:

as the answers says, the only two forces in the y axis are the normal force and the weight, and they balance each other. On the x axis, you have 20N to the right and the friction is a force that opposes the movement, so the 10N are to the left. The net force is 20 - 10 = 10N.

3 0

3 years ago

IrinaK [193]

Answer:

A

Explanation

i think its a not 100% sure though.

7 0

3 years ago

The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o

kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

$Y=Ae^{-kt}$

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

$\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}$

$Y=Ae^{-kt}$

$\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years$

hence time taken is equal to 14,156 years

5 0

3 years ago

A 12-V battery maintains an electric potential difference between two parallel metal plates separated by 10 cm. What is the elec

Sauron [17]

Answer:

The electric field between the plates is 120 V/m.

(c) is correct option.

Explanation:

Given that,

Potential difference = 12 volt

Distance = 10 cm = 0.1 m

We need to calculate the electric field between the plates

Using formula of electric field

$E = \dfrac{V}{d}$

Where, V = potential difference

d = distance between the plates

Put the formula

$E =\dfrac{12}{0.1}$

$E=120\ V/m$

Hence, The electric field between the plates is 120 V/m.

4 0

4 years ago

A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the ca

Leona [35]

Answer:

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

$F=ma$

$a=\dfrac{F}{m}$

$a=\dfrac{901}{1423}$

$a=0.63\ m/s^2$

Let v is the final speed of the car. Using third equation of motion to find it as :

$v^2-u^2=2ad$

$v^2=2ad+u^2$

$v^2=2\times 0.63\times 106+(26.4)^2$

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.

5 0

4 years ago