The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is
about 5 N and it is being pushed with 20 N of pressure. If there is 10 N of friction across the floor, what is the Net Force acting on the car?
A
Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.
B
Friction and the Normal Force are acting opposite the Applied Force, so the Net Force is 5 N, right.
C
The Net Force is 35 N, the addition of each of the Forces acting on the car and causing it to accelerate.
D
Net Force is equal to mass times acceleration so the Net Force is .5 kg times 9.8 m/s2 or roughly 5 N.
A
Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.
B
Friction and the Normal Force are acting opposite the Applied Force, so the Net Force is 5 N, right.
C
The Net Force is 35 N, the addition of each of the Forces acting on the car and causing it to accelerate.
D
Net Force is equal to mass times acceleration so the Net Force is .5 kg times 9.8 m/s2 or roughly 5 N.
1 answer:
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Due to equilibrium of moments:
1) The weight of the person hanging on the left is 250 N
2) The 400 N person is 3 m from the fulcrum
3) The weight of the board is 200 N
Explanation:
1)
To solve the problem, we use the principle of equilibrium of moments.
In fact, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.
The moment of a force is defined as:
where
F is the magnitude of the force
d is the perpendicular distance of the force from the fulcrum
In the first diagram:
- The clockwise moment is due to the person on the right is
where is the weight of the person and
is its distance from the fulcrum
- The anticlockwise moment due to the person hanging on the left is
where is his weight and
is the distance from the fulcrum
Since the seesaw is in equilibrium,
So we can find the weight of the person on the left:
2)
Again, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.
- The clockwise moment due to the person on the right is
where is the weight of the person and
is its distance from the fulcrum
- The anticlockwise moment due to the person on the left is
where is his weight and
is the distance from the fulcrum.
Since the seesaw is in equilibrium,
So we can find the distance of the person on the right:
3)
As before, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.
- The clockwise moment around the fulcrum this time is due to the weight of the seesaw:
where is the weight of the seesaw and
is the distance of its centre of mass from the fulcrum
- The anticlockwise moment due to the person on the left is
where is his weight and
is the distance from the fulcrum
Since the seesaw is in equilibrium,
So we can find the weight of the seesaw:
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