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m_a_m_a [10]
3 years ago
12

The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is

about 5 N and it is being pushed with 20 N of pressure. If there is 10 N of friction across the floor, what is the Net Force acting on the car?
A
Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.

B
Friction and the Normal Force are acting opposite the Applied Force, so the Net Force is 5 N, right.

C
The Net Force is 35 N, the addition of each of the Forces acting on the car and causing it to accelerate.

D
Net Force is equal to mass times acceleration so the Net Force is .5 kg times 9.8 m/s2 or roughly 5 N.

Physics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

A

Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.

Explanation:

as the answers says, the only two forces in the y axis are the normal force and the weight, and they balance each other. On the x axis, you have 20N to the right and the friction is a force that opposes the movement, so the 10N are to the left. The net force is 20 - 10 = 10N.

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<u>Principal</u><u> </u><u>focus</u><u> </u><u>of</u><u> </u><u>concav</u><u>e</u><u> </u><u>lens</u><u> </u><u>-</u><u> </u>

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