The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is
about 5 N and it is being pushed with 20 N of pressure. If there is 10 N of friction across the floor, what is the Net Force acting on the car?
A
Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.
B
Friction and the Normal Force are acting opposite the Applied Force, so the Net Force is 5 N, right.
C
The Net Force is 35 N, the addition of each of the Forces acting on the car and causing it to accelerate.
D
Net Force is equal to mass times acceleration so the Net Force is .5 kg times 9.8 m/s2 or roughly 5 N.
A
Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.
B
Friction and the Normal Force are acting opposite the Applied Force, so the Net Force is 5 N, right.
C
The Net Force is 35 N, the addition of each of the Forces acting on the car and causing it to accelerate.
D
Net Force is equal to mass times acceleration so the Net Force is .5 kg times 9.8 m/s2 or roughly 5 N.
1 answer:
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1) The most potential energy is at position A
2) The most kinetic energy is at position C
Explanation:
1)
The gravitational potential energy is the energy possessed by an object due to its position in a gravitational field, and it is given by the equation
where
m is the mass of the object
g is the acceleration of gravity
h is the height of the object relative to the ground
From the equation, we see that the potential energy is directly proportional to the heigth of the object: therefore, the roller coaster in this problem will have the most potential energy at its highest postion, so at position A.
2)
The total mechanical energy of the roller coaster at any point along the track is given by
where
PE is the potential energy
KE is the kinetic energy
Assuming there is no friction, the mechanical energy E is constant. This means that when PE increases, KE decreases, and when PE increases, KE decreases.
Therefore, the cart will have maximum kinetic energy when the potential energy is at minimum: and since the potential energy is directly proportional to the height of the track, this will occur at the lowest position, so at position C.
Learn more about kinetic and potential energy:
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