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m_a_m_a [10]
3 years ago
12

The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is

about 5 N and it is being pushed with 20 N of pressure. If there is 10 N of friction across the floor, what is the Net Force acting on the car?
A
Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.

B
Friction and the Normal Force are acting opposite the Applied Force, so the Net Force is 5 N, right.

C
The Net Force is 35 N, the addition of each of the Forces acting on the car and causing it to accelerate.

D
Net Force is equal to mass times acceleration so the Net Force is .5 kg times 9.8 m/s2 or roughly 5 N.

Physics
1 answer:
Ugo [173]2 years ago
3 0

Answer:

A

Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.

Explanation:

as the answers says, the only two forces in the y axis are the normal force and the weight, and they balance each other. On the x axis, you have 20N to the right and the friction is a force that opposes the movement, so the 10N are to the left. The net force is 20 - 10 = 10N.

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1. Calculati greutatea unui sac cu 5 kg de cartofi într-o zonă in care acceleratia gravitatională
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the weight is 49.1 N

Explanation:

The computation of the weight is shown below:

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6 0
3 years ago
A very long wire generates a magnetic field of 0.0020x 10^-4 T at a distance of 10 mm. What is the magnitude of the current? A)
zimovet [89]

Answer:

2*10^-<em>5</em>

Explanation:

<em>B=</em><em>I</em><em>L</em>

<em>I=</em><em>B</em><em>/</em><em>L</em>

<em>I=</em><em>0</em><em>.</em><em>0</em><em>0</em><em>2</em><em>0</em><em>*</em><em>1</em><em>0</em><em>^</em><em>-</em><em>4</em><em>/</em><em>1</em><em>0</em>

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6 0
3 years ago
A ball is thrown w a speed of 30m/s at an angle of 10. When is the vertical component of the velocity equal to zero
irga5000 [103]

Now the vertical velocity of the ball thrown at an angle 10° is given as

Voy(initial vertical velocity)= 30m/s x sin 10

Voy(initial vertical velocity)= 5.2m/s

Now the ball is decelerating with an acceleration due to gravity equivalent to 9.8m/s^2.

Let Vy be the final velocity and that is equal to zero in this case.

Now

Vy= Voy- tx9.8

Where t is the time at which the vertical velocity becomes 0.

Substituting the values we get

0= 5.2-tx9.8

9.8t=5.2

t=0.53 secs



5 0
2 years ago
Read 2 more answers
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