Question

Pls tell me the correct option

Answer 1

Answer:

b. $\frac{1}{16}$

Step-by-step explanation:

A = {2, 3}

B = {4, 6}

C = set of all possible fractions where, the numerators are in set A and the denominators are found in Set B

The 4 possible fractions we can get for set C are as follows:

Set C: { $\frac{2}{4}$ , $\frac{2}{6}$ , $\frac{3}{4}$ , $\frac{3}{6}$ }

Multiply all to get the product of all elements in Set C:

$\frac{2}{4}*\frac{2}{6}*\frac{3}{4}*\frac{3}{6}$

Simplify where necessary

$\frac{1}{2}*\frac{1}{3}*\frac{3}{4}*\frac{1}{2}$

$\frac{1*1*3*1}{2*3*4*2}$

$\frac{3}{48}$

Simply further

$\frac{1}{16}$

Answer 2

Answer: I would go with C I hope i am right!!

Step-by-step explanation: