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2 years ago

Pls tell me the correct option

Mathematics

2 answers:

katrin2010 [14]2 years ago

8 0

Answer:

b. $\frac{1}{16}$

Step-by-step explanation:

A = {2, 3}

B = {4, 6}

C = set of all possible fractions where, the numerators are in set A and the denominators are found in Set B

The 4 possible fractions we can get for set C are as follows:

Set C: { $\frac{2}{4}$ , $\frac{2}{6}$ , $\frac{3}{4}$ , $\frac{3}{6}$ }

Multiply all to get the product of all elements in Set C:

$\frac{2}{4}*\frac{2}{6}*\frac{3}{4}*\frac{3}{6}$

Simplify where necessary

$\frac{1}{2}*\frac{1}{3}*\frac{3}{4}*\frac{1}{2}$

$\frac{1*1*3*1}{2*3*4*2}$

$\frac{3}{48}$

Simply further

$\frac{1}{16}$

Hoochie [10]2 years ago

5 0

Answer: I would go with C I hope i am right!!

Step-by-step explanation:

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Natalka [10]

Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
0.8+2.24+1.75+0.7=5.49

5.49
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2 years ago

Why do banks charge fees?

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3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

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Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

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Answer:

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