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Ugo [173]
3 years ago
15

What is the sum? Thank you!

Mathematics
2 answers:
Daniel [21]3 years ago
5 0

Answer:

1835014

Step-by-step explanation:

Nady [450]3 years ago
4 0

Answer:

2097150

Step-by-step explanation:

sum=(2(1-1048576))/(1-2)

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Sin 2A = sinA is true when A=?​
strojnjashka [21]
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8 0
3 years ago
A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
kyle drew tree line segments with these lenngths: 2/4" , 2/3" , 2/6" list the fractions in order from least to graiter
exis [7]
First you find a common denominator, which is 12 ( as 4,3 and 6 all go into 12). So 2/4 becomes 6/12, as 4 multiplied by 3 is 12 and whatever you do to the denominator you must do to the numerator. Then 2/3 becomes 8/12. And 2/6 becomes 4/12. If you put these in order the answer is:

2/6, 2/4, 2/3

6 0
3 years ago
I will rate them brainliest and 5 stars and thanks to whoever answers the part a and part b correctly
vodka [1.7K]

Answer:

A=40

B=.625

Step-by-step explanation:

1.25/.25 is 5

1/.25 is 4

.5/.25 is 2

5 x 4 x 2 is 40

multiply all of the sides together

or

multiply the boxes sides together then x 40

4 0
3 years ago
Find one value of x for which f(2) & f(x)=4
igomit [66]
The first thing we must do for this case is to observe the value of the y coordinate for a given value of the x coordinate.
 We have then:
 f (x) = - 4: occurs when x = 0 
 On the other hand, for x = 2 we have:
 f (2) = - 2
 Answer:
 f (x) = - 4: occurs when x = 0
 
f (2) = - 2
4 0
3 years ago
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