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Answer:
Horizontal distance between the log and the bridge when the stone is released = 17.24 m
Step-by-step explanation:
Height of bridge, h = 50.8 m
Speed of log = 5.36 m/s
We need to find the horizontal distance between the log and the bridge when the stone is released, for that first we need to find time taken by the stone to reach on top of log,
We have equation of motion. s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 50.8 m
Substituting,
s = ut + 0.5 at²
50.8 = 0.5 x 9.81 x t²
t = 3.22 seconds,
So log travels 3.22 seconds at a speed of 5.36 m/s after the release of stone,
We have equation of motion. s = ut + 0.5 at²
Initial velocity, u = 5.36 m/s
Acceleration, a = 0 m/s²
Time, t = 3.22 s
Substituting,
s = ut + 0.5 at²
s = 5.36 x 3.22 + 0.5 x 0 x 3.22²
s = 17.24 m
Horizontal distance between the log and the bridge when the stone is released = 17.24 m
-12 Celsius because that would equal 10.4 degrees
T(110) is used to calculate the value of T when w = 110.
<h3>
Linear equation</h3>
A linear equation is in the form:
y = mx + b
where y, x are variables, m is the rate of change (slope) and b is the y intercept.
Given the linear equation:
T(w) = 530 - w
Hence T(110) is used to calculate the value of T when w = 110.
Find out more on Linear equation at: brainly.com/question/13763238
Answer:
Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
Data given
Confidence =0.99 or 99%
represent the significance level
n =16 represent the sample size
We don't know the population deviation 
Solution for the problem
For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:
We know that 
so then 
and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:
"=T.INV(0.005;15)" and we got 
on this case since the distribution is symmetric we know that the other critical value is 
