Answer:
Option 3 (79−3x=12x+19)
Step-by-step explanation:
When replacing x with 4 you will get the answer 67 = 67, which is true! The other three options are not true when replacing x with 4.
Step-by-step explanation:
Given that,
a)
X ~ Bernoulli
and Y ~ Bernoulli 
X + Y = Z
The possible value for Z are Z = 0 when X = 0 and Y = 0
and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0
If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,
Therefore Z is a Bernoulli random variable
b)
If X and Y can not be both equal to 1
then,
or 
and 

c)
If both X = 1 and Y = 1 then Z = 2
The possible values of the random variable Z are 0, 1 and 2.
since a Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution
Answer:
The answer is 5w+12.
Step-by-step explanation:
Combine like terms:
(3w+7)+(2w+5)
5w+12
You will get $2.03 back in change