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Marrrta [24]
2 years ago
7

What is the frequency of light?( I just want to confirm )​

Chemistry
2 answers:
Xelga [282]2 years ago
7 0

Answer:

The frequency of light ranges from 430 trillion hertz to 750 trillion hertz

Explanation:

Phantasy [73]2 years ago
3 0
<h2><em>What is the frequency of light?</em></h2>

  • <em>The frequency of visible light is referred to as color, and ranges from 430 trillion hertz, seen as red, to 750 trillion hertz, seen as violet.</em>

<em>Explanation:</em>

  • <em>Visible light falls in the range of the EM spectrum between infrared (IR) and ultraviolet (UV). It has frequencies of about 4 × 1014 to 8 × 1014 cycles per second, or hertz (Hz) and wavelengths of about 740 nanometers (nm) or 2.9 × 10−5 inches, to 380 nm (1.5 × 10−5 inches)</em>

<em>hope</em><em> </em><em>it</em><em> helps</em>

You might be interested in
Determine the percent composition of potassium dichromate, K2Cr2O7.
bulgar [2K]

Answer:

Option E is the correct one

Explanation:

K₂Cr₂O₇ → Potassium dichromate

A ionic salt which its molar mass is 294.18 g/m

It is composed by 2 mol of K, 2 mol of Cr and 7 mol of O

2 mol of K = 78.2 g

2 mol of Cr = 104 g

7 mol of O = 112 g

In 294.2 g of compound we have __78.2 g K __ 104 g Cr ___ 112 g O

Let's calculate the percent

(78.2 / 294.2) .100 = 26.59% K

(104 / 294.2) .100 = 35.35% Cr

(112 / 294.2) . 100 = 38.06 % O

4 0
2 years ago
Electrons help create bonds between elements as they lie on the outside of an<br> atom.
andrezito [222]
Uh , what’s the question ?
6 0
3 years ago
Moles of NaOH used in titration mole NaOH Moles of HC2H3O2 neutralized by NaOH mole HC2H3O2 Molarity of HC2H3O2 M HC2H3O2 Grams
Marta_Voda [28]

For the given picture:

Moles of NaOH = A × 0.04183 moles

Moles of HC2H3O2 neutralized = (A × 0.04183) moles

Mass of HC2H3O2 = (2.0598 × A)g

Percent (m/v) HC2H3O2 in vinegar = (411.96 × A)%

<h3>What is molarity?</h3>

A mole is the unit of measurement used for chemicals, hence the term "molarity". Molarity, also known as solution molarity, is a technique for calculating the amount of a substance in a particular chemical solution.

Let molarity of NaOH be A from picture, volume of vinegar used is 5ml.

Now, average volume of NaOH used for titration = 0.04183 L (as per picture)

Molarity of NaOH = A

So,

(C7) Moles of NaOH = A × 0.04183

as 1 mol NaOH neutralizes 1 mol CH3COOH

(A × 0.04183) moles will neutralize (M × 0.04183) moles CH3COOH

(C8) moles of HC2H3O2 neutralized = (A × 0.04183)

Molar mass of HC2H3O2 is 60 gm/mol

So mass of (M × 0.04183) moles is (A × 0.04183 × 60) = (2.0598 × A)

(C9) Grams HC2H3O2 = (2.0598 × A)

Now volume of (vinegar+acetic acid) that was titrated = 5ml or 0.005 L

Now, M₁V₁ = M₂V₂

where,

M₁ = A

V₁ = 0.04183L

M₂ = ?

V₂ = 0.005L

put all values, value of V must be in liters

M₂ = (0.04183 × A)/0.005 = 8.366A Molar

(C10) molarity of HC2H3O2 = 8.366A Molar

Now grams of HC2H3O2 is taken from C9 and volume of vinegar is 0.005L

(C11)so mass of acetic acid/volume of vinegar(m/v)

= [(2.0598 × A)/0.005]

= (411.96 × A)%

To know more about molarity, visit:

brainly.com/question/2817451

#SPJ1

The complete question is as follows:

4 0
1 year ago
1. How many joules must be added to 10.0 g of water to raise its temperature from 10°C to<br> 15°C?
weqwewe [10]

Answer:

209.3 Joules require to raise the temperature from 10 °C to 15 °C.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass of water = 10 g

initial temperature T1= 10 °C

final temperature T2=  15 °C

temperature change =ΔT= T2-T1 = 15°C - 10°C = 5 °C

Energy or joules added to increase the temperature Q = ?

Solution:

We know that specific heat of water is 4.186 J/g .°C

Q = m × c × ΔT

Q = 10 g × 4.186 J/g .°C × 5 °C

Q = 209.3 J

6 0
3 years ago
Do compounds with different molecular formulas have different chemical properties
Ugo [173]
Saying I have two different compounds with different molecular formula. One is compound NaCl, the other one is compound H2O. They will have different chemical properties such as their melting and boiling point. Therefore the answer is Yes.
7 0
3 years ago
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