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3 years ago

What is happening to the temperature of the substance BEFORE AND AFTER the phase changes?

Chemistry

1 answer:

Neporo4naja [7]3 years ago

5 0

First off, you must realize that the phase changes are marked by the points B and D on the graph. They are level because all of the energy (or heat) being added is being consumed by the physical process. So The temperature is increasing before the phase change, and after the phase change. The moments before and after are represented by points A, C, and E.

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What is an example of potential energy and kentic energy?

lana [24]

Potential energy is stored energy. Kinetic energy involves movement.

If a ball is on the top of a hill, it has the most potential energy on the very top of the hill. The kinetic energy is also 0 at this point.

If the ball rolls down the hill, potential energy decreases while kinetic increases.

simple example

3 0

3 years ago

Read 2 more answers

A car is traveling 83.3 kilometers per hour. What is its speed in miles per minute? One kilometer = 0.62 miles.

Leya [2.2K]

Hi. 2fouls! :)

First convert the number from kilometer to miles:
$83.3*0.62$
$=51.646 miles$

Now to find the miles per minutes,divide the miles per hours by 60 (the amount of minutes in an hour.)

$51.646/60$
$=0.860766667$

The car is travelling at a speed of 0.860766667 miles/minute.

Hope this helps.
-Benjamin

3 0

3 years ago

Read 2 more answers

"calculate the ratio of the velocity of hydrogen molecules to the velocity of carbon dioxide molecules at the same temperature"

Ne4ueva [31]

Answer: 1:4.69

Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

Ua/Ub = 4.69

Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

which implies hydogen is about 4.69 times faster than carbon dioxide.

8 0

3 years ago

Helpppppp helpppppp helppppp

soldier1979 [14.2K]

where is the diagram?

without the diagram i can't help

7 0

3 years ago

The chemical equation of rusting of iron is given

artcher [175]

Answer:

${ \tt{(a). { \bf{reactants : { \tt{iron \: and \: oxygen}}}}}} \\ { \bf{products : { \tt{iron(iii)oxide}}}} \\ \\ { \tt{(b).}} \: { \bf{1.204 \times {10}^{24} \: atoms}} \\ { \tt{(c).}} \: { \tt{4Fe +3 O _{2} → 2Fe _{2}O _{3}}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}$

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2 years ago