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3 years ago

What is happening to the temperature of the substance BEFORE AND AFTER the phase changes?

Chemistry

1 answer:

Neporo4naja [7]3 years ago

5 0

First off, you must realize that the phase changes are marked by the points B and D on the graph. They are level because all of the energy (or heat) being added is being consumed by the physical process. So The temperature is increasing before the phase change, and after the phase change. The moments before and after are represented by points A, C, and E.

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Ghella [55]

Answer:

I would say C

Explanation: Hope this helped

4 0

3 years ago

Read 2 more answers

PLZ HELP QUICKLY!!

frutty [35]

Answer:

Robert Hooke.

Anton van Leeuwenhoek.

Matthias Schleiden.

Theodor Schwann.

Rudolf Virchow.

Explanation:

6 0

3 years ago

NaOH has a molarity of 2.5 M and a volume of 4 Liters, how many moles are in<br> the solution?

Inga [223]

Answer:

10. mol NaOH

Explanation:

2.5 M = 2.5 mol/L

2.5 mol/L * 4 L = 10. mol

7 0

3 years ago

A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit

Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

$\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}$

$P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}$

$P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times 35.0} = 0.776969038566$

∴ The final pressure P₂ ≈ 0.78 atm.

4 0

3 years ago

The solubility of acetanilide in hot water (5.5 g/100 ml at 100∘C) is not very great, and its solubility in cold water (0.53 g/

Olin [163]

Answer:

89.4%

Explanation:

Initially, there is 5.0 of the acetanilide in 100 mL of water, then the solution is chilled at 0ºC. The solubility represents the amount that the solvent (water) can dissolve of the solute (acetanilide). So, at 0ºC, 100 mL of water can dissolve till 0.53 g of the compound, the rest will precipitate and will be recovered.

So, the mass that is recovered is 5.0 - 0.53 = 4.47 g

The percent recovery is:

(4.47/5)x100% = 89.4%

8 0

4 years ago