The coefficient for hydrogen in the balanced equation of solid molybdenum(iV) oxide with gaseous hydrogen is 2
Explanation
Coefficient is defined to as a number in front of a chemical formula in a balanced chemical equation.
The reaction of molybdenum (iv) oxide with gaseous hydrogen is as below,
MoO2 + 2 H2→ Mo +2 H2O
From balanced equation above the coefficient for H2 is 2 since the number in front of H2 is 2
Moles = 15.5 g / 40 g/mol = 0.3875 mol
M = 0.3875 mol / 0.250 L = 1.55M
Answer:

The prefix "Tetra" implies 4 Bromine atoms. The prefix "Deca" implies 10 fluorine atoms.
Answer:
0.1832 moles of ethyl acetate (
)
Explanation:
1. Find the balanced chemical equation:
In the production of ethyl acetate, the acetic acid
reacts with ethanol to produce ethyl acetate
and water, that is:

2. Find the theoretical maximum moles of ethyl acetate
:
As the problem says that the acetic acid
is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced:
