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3 years ago

How much iron(III) oxide is produced? Answer in units of g.

Chemistry

1 answer:

Ronch [10]3 years ago

6 0

Answer:

Iron(III) oxide or ferric oxide is the inorganic compound with the formula Fe 2 O 3.It is one of the three main oxides of iron, the other two being iron(II) oxide (FeO), which is rare; and iron(II,III) oxide (Fe 3 O 4), which also occurs naturally as the mineral magnetite.

Chemical formula: Fe₂O₃

Molar mass: 159.687 g·mol−1

Density: 5.25 g/cm³

Solubility in water: Insoluble

Explanation:

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3 years ago

For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o_{(Cu^{2+}/Cu)}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)$

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Hence, the value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

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Read 2 more answers

Determine how many formula units are in 2.35 moles of lithium phosphite?

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Answer:

Determine how many formula units are in 2.35 moles of lithium phosphite?

Explanation:

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3 years ago

A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon

ikadub [295]

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<u>Explanation:</u>

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