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SOVA2 [1]
3 years ago
10

How many mol of phosphorus are obtained if 74.85 mol of carbon is used​

Chemistry
1 answer:
mixer [17]3 years ago
6 0

Answer:

34.73

Explanation:

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2. Have someone hold the mirror for you, slowly move at least 3 m away from the it.
Ahat [919]

Answer: Slowly move at least 3 m away from the side mirror. Observe your image as you ... Compare the images formed in different mirrors. ... but if i stand 3m away, even though there is no light, it reflects the other material it can ... is transparent so you cannot see yourself much in the mirror, that is my observation.

Explanation:

3 0
3 years ago
List properties of ions.
miskamm [114]

Hard.

Form crystal lattices not molecules.

Good insulators.

High melting points/ Boiling Points.

Conduct electricity when dissolved in water or as a liquid.

Solids do not conduct electricity.

5 0
3 years ago
If a sample of this compound contains 6.4×1022 sodium ions, how many sulfide ions does it contain?
Effectus [21]
The ionic compound formed by sodium and sulfur is Na2S, whose name is sodium sulfide.


The chemical formula tells you the ratio between the two elements is 2Na/1S or 1S/2Na

So, if you have 6.4 * 10^22 sodium ions, you will have

6.4 * 10^22 Na * 1S / 2Na = 3.2 * 10^22 S.


Answer: the compound contains 3.2 * 10^22 sulfide ions.
5 0
3 years ago
Calculate the no. of moles in 25gm of calcium phosphate <br><br>Plz Fast Urgent
madreJ [45]

Answer:

0.162 mol

Explanation:

n=m/M

M= 20*3 + 15*2 + 8*4*2

M=154 g/mol

n=25g/154g/mol

n=0.162 mol

7 0
3 years ago
What mass of calcium hydroxide is formed when 10.0g of calcium oxide reacts with 10.0g of water?
nexus9112 [7]

The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with  10.0 g of water is 13.024 grams


calculation

from the equation

CaO + H2O → Ca(OH)2,

 1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2

find the moles of each reactant

moles=mass/molar mass

moles of CaO= 10 g/56 g/mol=0.179 moles

moles of H2O = 10 g/18 g/mol 0.556  moles

CaO is the limiting reagent  therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles

mass= moles x molar mass

= 0.176 moles x  74 g/mol = 13.024  grams

7 0
4 years ago
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