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SOVA2 [1]
3 years ago
10

How many mol of phosphorus are obtained if 74.85 mol of carbon is used​

Chemistry
1 answer:
mixer [17]3 years ago
6 0

Answer:

34.73

Explanation:

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If you add acid or base to water how will the ph change
Bad White [126]
Adding an acid to water will decrease the pH as acids have a pH less than 7 and the pH of water is 7. Adding a base will increase the pH because the pH of bases is above 7.
3 0
3 years ago
Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide: 2Na
Oxana [17]

Answer: 65.7 gram

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} I_2=\frac{55.6g}{254g/mol}=0.219moles

2NaI(aq)+Cl_2(g)\rightarrow I_2(s)+2NaCl(aq)

According to stoichiometry :

1 mole of I_2 are produced by = 2 moles of NaI

Thus 0.219 moles of I_2 will be produced by =\frac{2}{1}\times 0.219=0.438moles of NaI

Mass of NaI=moles\times {\text {Molar mass}}=0.438moles\times 150g/mol=65.7g

Thus 65.7 g of NaI, must be used to produce 55.6 g of iodine

8 0
3 years ago
When boiling water is the particles expanding?
Juli2301 [7.4K]
When water is boiling the particles in the liquid are not expanding. This also applies for other liquids. Particles do not expand, it is only the volume they take up that expands. When water is boiling, the particles are rather escaping the liquid phase by undergoing a phase change which forms the particles into the gaseous phase.
5 0
3 years ago
Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c
nirvana33 [79]

Answer:

pKb = 10.96

Explanation:

Tartaric acid is a dyprotic acid. It reacts to water like this:

H₂Tart  +  H₂O  ⇄  H₃O⁺   +  HTart⁻         Ka1

HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2

When we anaylse the base, we have

Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1

HTart⁻  +  H₂O  ⇄  OH⁻  +    H₂Tart          Kb2

Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1  →   1×10⁻¹⁴ / 9.20×10⁻⁴  = 1.08×10⁻¹¹

so pKb = - log Kb2   → - log 1.08×10⁻¹¹ = 10.96  

7 0
3 years ago
Read 2 more answers
In a given chemical reaction the energy of the products is greater than the energy of the reactance which statement is true for
IceJOKER [234]

Answer:

Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.

6 0
4 years ago
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