Answer:
6,226 tiles of 9 in are needed to cover an area of 400 square feet
Step-by-step explanation:
Let
A -----> an area in square feet
t(A) ---> the total number of 9 in. tiles needed
we have
For A=400 ft^2
substitute in the equation and solve for t
That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet
20 in I’m for sure on this answer
Connect the dots to each other
The smaller triangle is 1/6 the size of the large one ( 5/30 = 1/
Area is squared 1/6 ^2 = 1/36
Multiply the area of the large triangle by 1/36:
270 x 1/36 = 270 /36 = 7.5
The area is 7.5 cm^2
The answer is A.
9514 1404 393
Answer:
12 liters
Step-by-step explanation:
The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...
v = k·s·h . . . . . for s stoves running h hours
Then the value of k is ...
k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour
Then the volume of kerosene required for 7 stoves and 18 hours is ...
v = (2/21)·s·h
v = (2/21)(7)(18) = 12 . . . liters
