Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Answer:
7.18 light-years
Step-by-step explanation:
6.8 x 10^13 = 68,000,000,000,000
9.46 x10 ^12 = 9,460,000,000,000
6.8 x 10^13 * 1 light year / 9.46 x 10^12 = 7.188 light years.
Have a Merry X-MAS Plz MArk Branilest
Answer:
last one
Step-by-step explanation:
x = width
x+6 = length
Area = length times width
x(x + 6) = 
+ 6x
+ 6<em>x = 114 (subtract 114 from both sides) </em>
<em /><em> + 6x -114 = 0</em>
