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1 year ago

The human body has an average density of 979 kg/m3 , what fraction of a person is submerged when floating gently in fresh water?

Physics

1 answer:

FromTheMoon [43]1 year ago

4 0

A person is submerged of about 97.9%.

The average density of the human body is given as 979 kg/ m³.

<h3>Define Law of floatation.</h3>

Law of floatation can be defined as the volume of the liquid displaced when a body floats on the liquid surface is equal to the body submerged in the water.

As body has the stable equilibrium state, the buoyancy of the fluid will be equal to the weight.

Weight of the body floating = Weight of the body immersed in fluid

Law of floatation = Density of the floating object / density of fluid

As fluid is the freshwater here, the density of fluid will be 1000 kg/ m³.

= (979 kg/ m³) / ( 1000 kg/ m³)

= 97.9 %

A person is submerged when floating gently in fresh water about 97.9%.

Learn more about law of floatation,

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Answer:

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Explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³

From the question above,

D = m/v.............................. Equation 1

Where D = density, m = mass, v = volume.

Note: The volume of the liquid is equal to the volume of the height occupied by the liquid in the container

Since the tank is cylindrical,

v = πr²h........................ Equation 2

Where r = radius of the the tank, h = height of the liquid in the tank

Substitute equation 2 into equation 1

D = m/(πr²h)............... Equation 3

Given: m = 14014 kg, r = 1.35 m, h = 3.45 m, π = 3.14

Substitute into equation 3

D = 14014/(3.14×1.35²×3.45)

D = 14014/19.74

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Answer:

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Answer:

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