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dmitriy555 [2]
11 months ago
7

The human body has an average density of 979 kg/m3 , what fraction of a person is submerged when floating gently in fresh water?

Physics
1 answer:
FromTheMoon [43]11 months ago
4 0

A person is submerged of about 97.9%.

The average density of the human body is given as 979 kg/ m³.

<h3>Define Law of floatation.</h3>

    Law of floatation can be defined as the volume of the liquid displaced when a body floats on the liquid surface is equal to the body submerged in the water.

As body has the stable equilibrium state, the buoyancy of the fluid will be equal to the weight.

Weight of the body floating = Weight of the body immersed in fluid

  Law of floatation = Density of the floating object / density of fluid

 As fluid is the freshwater here, the density of fluid will be 1000 kg/ m³.

                               = (979 kg/ m³) / ( 1000 kg/ m³)

                               = 97.9 %

A person is submerged when floating gently in fresh water about 97.9%.

Learn more about law of floatation,

brainly.com/question/17032479

#SPJ4

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Explanation:

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4 0
3 years ago
This question is related to inertia:
luda_lava [24]
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3 0
3 years ago
Which pigments are mixed to produce Blue?
romanna [79]

Answer:

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5 0
3 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = \frac{F_{1} }{4} = \frac{27.2}{4} = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0
3 years ago
How many times longer than the length of one year is the age of the universe?
Len [333]
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