Answer:
See the explanation below.
Explanation:
Density will remain the same since density is the relationship between mass and volume. As we can see in the equation below.
![Ro=m/V](https://tex.z-dn.net/?f=Ro%3Dm%2FV)
where:
Ro = density = 2.5 [g/cm³]
m = mass [g]
V = volume [cm³]
In such a way that when the glass is broken the small fragments retain the same density ratio. That is, each fragment has a small mass and a small volume. That's why the density remains the same.
Answer:
The length of the Mercury column of thermometer at ice point is 20mm and 220mm at steam point . when the same Thermometer is placed in contact with another body ,it reads 5°c.what will the length of the Mercury column at the temperature?
Answer:
Explanation:
Given
charge of first body ![q_1=2.5\ mu C](https://tex.z-dn.net/?f=q_1%3D2.5%5C%20mu%20C)
charge of second body ![q_2=-3.5\ mu C](https://tex.z-dn.net/?f=q_2%3D-3.5%5C%20mu%20C)
Particle 1 is at origin and particle 2 is at ![x=0.6\ m](https://tex.z-dn.net/?f=x%3D0.6%5C%20m)
third Particle which charge +q must be placed left of
because it will repel the q charge while
will attract it
suppose it is placed at a distance of x m
![F_{1q}=\frac{kq(2.5)}{x^2}](https://tex.z-dn.net/?f=F_%7B1q%7D%3D%5Cfrac%7Bkq%282.5%29%7D%7Bx%5E2%7D)
![F_{2q}=\frac{kq(-3.5)}{(0.6+x)^2}](https://tex.z-dn.net/?f=F_%7B2q%7D%3D%5Cfrac%7Bkq%28-3.5%29%7D%7B%280.6%2Bx%29%5E2%7D)
![F_{1q}+F_{2q}=0](https://tex.z-dn.net/?f=F_%7B1q%7D%2BF_%7B2q%7D%3D0)
![\frac{kq(2.5)}{x^2}+\frac{kq(-3.5)}{(0.6+x)^2}=0](https://tex.z-dn.net/?f=%5Cfrac%7Bkq%282.5%29%7D%7Bx%5E2%7D%2B%5Cfrac%7Bkq%28-3.5%29%7D%7B%280.6%2Bx%29%5E2%7D%3D0)
![\frac{kq(2.5)}{x^2}=\frac{kq(3.5)}{(0.6+x)^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bkq%282.5%29%7D%7Bx%5E2%7D%3D%5Cfrac%7Bkq%283.5%29%7D%7B%280.6%2Bx%29%5E2%7D)
![\frac{0.6+x}{x}=(\frac{3.5}{2.5})^{0.5}](https://tex.z-dn.net/?f=%5Cfrac%7B0.6%2Bx%7D%7Bx%7D%3D%28%5Cfrac%7B3.5%7D%7B2.5%7D%29%5E%7B0.5%7D)
![0.6+x=1.1832x](https://tex.z-dn.net/?f=0.6%2Bx%3D1.1832x)
![x=3.27\ m](https://tex.z-dn.net/?f=x%3D3.27%5C%20m)
Answer:
he fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Explanation:
Let's pose the solution of this problem, to be able to analyze the firm affirmations.
When the person is falling, the weight acts on them all the time, initially the rope has no force, but at the moment it begins to lash it exerts a force towards the top that is proportional to the lengthening of the rope.
The equation for this part is
Fe - W = m a
k x - mg = m a
As the axis of rotation is located at the top where they jump, there is a torque.
What is it
Fe y - W y = I α
angular and linear acceleration are related
a = α r
Fe y - W y = I a / r
In the fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true