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madam [21]
3 years ago
5

Solve for x ax + by = 2abx Please help

Chemistry
1 answer:
QveST [7]3 years ago
4 0
Ax+by=2abx
Subtract 2abx from both sides
-2abx+ax+by=0
Subtract BY from both sides
-2abx+ax=-by
Factor out the x
X(-2ab+a)=-by
Divide both sides by -2ab+a
X=-by/-2ab+a

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In a water molecule, what type of bond forms between the oxygen and hydrogen atoms
goldenfox [79]
Covalent bond forms between the oxygen and hydrogen atoms.

(I attached a picture that could help)

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7 0
2 years ago
A scientist needs to collect a 0.050 mole sample of helium, but needs to know how large his helium container should be. What vol
Mumz [18]

We can use the ideal gas equation:

PV = nRT

P = 202.6kPa = 202600 Pa (You have to multiply by 1000)

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We will have to convert from Pa to atm or viceversa.

101325 Pa________1 atm

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8 0
4 years ago
A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO
Darya [45]

Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL

Putting values in above equation, we get:

2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL

M_2=0.336M

Thus, the concentration of NaOH is, 0.336 M

3 0
3 years ago
What is the volume of 2.0 mol CO2 at STP?
Andrew [12]

Answer:

44.8 litres is the answer to the question

6 0
3 years ago
Which statement explains how the bands in the crystal of a metal are like atomic orbitals?
algol [13]
Please provide the choices here.

The similarity of the bands in the crystal of a metal to the atomic orbitals can be explained by the band theory of metals. In an atom, when the electrons get excited, the electrons jumps to a higher orbital so as to reach equilibrium. This is analogous to the electrons in the metals which also jumps to another band once excited by an external energy (e.g. electrical energy). 
3 0
4 years ago
Read 2 more answers
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