Answer:
32.3%
Explanation:
Percent yield is defined as:
Actual yield (125.5g) / Theoretical Yield * 100
To find theoretical yield we have to find the moles of aluminium. As 2 moles of Al produce 2 moles of AlCl3, the moles of Al = Moles AlCl3.
With these moles we can find the mass assuming a 100% of yield (Theoretical Yield) as follows:
<em>Moles Al = Moles AlCl3 (Molar mass Al = 26.98g/mol)</em>
72g Al * (1mol / 26.98g) = 2.67 moles AlCl3
<em>Mass AlCl3 (Molar mass: 133.34g/mol)</em>
2.67 moles AlCl3 * (133.34g / mol) = 355.8g AlCl3
Percent Yield = 125.5g / 355.8g * 100 =
<h3>32.3% </h3>
Answer:
Explanation:
H = 1
C = 12
O = 16
Acetylene, HC≡CH = 2+24 = 26
H2O = 2 + 16 = 18
In XS oxygen, one HC≡CH yields one H2O
26 g HC≡CH ==> 18 g H2O
2000 g HC≡CH ==> 2000*18/26 g H2O = 1384.6154 g H2O
An example of a base in chemistry would be like soap or lye
PH of acidic buffer = pKa + log [CH₃COONa - HCl] / [CH₃COOH + HCl]
pKa of CH₃COOH = 4.74
Concentration of acetic acid in buffer = 2.0 M
Concentration of sodium acetate = 1.0 M
Concentration of HCl must add = x
pH = 4.74 + log (1-x) / (2+x) = 4.11
x = concentration of HCl must be added = 0.43 M
number of moles of HCl = M * V = 0.43 * 1 = 0.43 mol
mass of HCl must be added = 0.43 * 36.5 = 15.7 g
