Answer:
Partial pressure of oxygen = 190 mmHg
Explanation:
From the question;
Mixture contains only nitrogen and oxygen
Total pressure of the mixture = 480 mmHg
Partial pressure of nitrogen = 290 mmHg
Dalton's law states that the pressure of a system is as a result of the sum of the partial pressures of the individual components of the mixture. This means that in this mixture;
Pressure of mixture = Partial Pressure of Nitrogen + Partial Pressure of Oxygen
480 = 290 + Partial pressure of oxygen
Partial pressure of oxygen = 480 - 290
Partial pressure of oxygen = 190 mmHg
Answer:
C. grinding the reactants into finer grains
Explanation: I just took the assignment.
<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.
<u>Explanation:</u>
To calculate the wavelength, we use Planck's equation, which is:

where,
E = Energy of 1 photon = 
h = Planck's constant = 
c = speed of light = 
= wavelength = ?
Putting values in above equation, we get:

The range of wavelength of blue light lies in range of 500 nm - 435 nm
The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm
Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.
Answer : The nutritional Calories per gram of the candy are, 5.36 calories
Explanation :
First we have to calculate the amount of heat.

where,
q = heat = ?
c = specific heat = 
= change in temperature = 
Now put all the given values in the above formula, we get:


Now we have to calculate the heat for per gram of sample.
Heat = 
Now we have to calculate the heat in terms of calories.
As, 1 nutritional Calories = 1000 calories
and, 1 calories = 4.2 J
As, 4.2 J = 1 calories
So, 22510 J = 
Therefore, the nutritional Calories per gram of the candy are, 5.36 calories