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Lady bird [3.3K]
3 years ago
7

Kepler’s first law states that:

Physics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

Kepler's first law means that planets move around the Sun in elliptical orbits. An ellipse is a shape that resembles a flattened circle. ... It is zero for a perfect circle.

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High pressure<br> system the air moves (up/down) and brings<br> (good/bad) weather
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high pressure system in the air moves up and brings good weather

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Oscilaţia are un caracter ... , mişcarea se repetă aproape identic după un ... De timp. B) Dacă amplitudinea oscilaţiei rezultan
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3 years ago
To which series would the emitted light belong if an electron in a hydrogen atom underwent a transition from level n = 5 to leve
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So we want to know in which series would the emitted light belong if the electron in a hydrogen atom would go from the energy level n=5 to n=1. The correct answer is Lyman series. Complete Lyman series is from energy level n=6 to n=1. All of the wavelengths in the Lyman series are in the ultraviolet part of the electromagnetic spectrum. 
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4 years ago
____________occurs when an object travels in a curved path.
labwork [276]

Answer:

Acceleration

Explanation:

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So, if an object travels in a curved path, it changes velocity, and, thus, accelerates. This acceleration must be tied to a force. ... Therefore, whenever an object travels in a curved path, there must be an unbalanced force acting upon it. It is important to understand that all this may occur without a change in speed.t

4 0
3 years ago
Tarzan (mT=85.0 kg) is perched on a cliff 16.0 m above Jane. Jane is in the foreground is looking forwards. In the background, T
poizon [28]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Part A

The velocity of Tarzan is   v_T = 17.7 \ m/s

Part B

The percentage loss of kinetic energy is  %-loss  = 61.4%

Part C

The speed would be exactly the same

Explanation:

From the question we are told that

       The mass of Tarzan is m = 85.5 \ kg

          The height of the cliff is h = 16.0 \ m

           

From the law of conservation of energy

             PE = KE

Where PE is the potential energy of Tarzan at the top of the cliff which is mathematically represented as

            PE = mgh

        KE is the kinetic energy of Tarzan as he swings toward jane and is mathematically represented as

           KE = \frac{1}{2} mv^2_T

  So

            mgh = \frac{1}{2}m v_T^2

=>        gh = \frac{1}{2} v_T^2

Substituting values

             9.8 * 16 = \frac{1}{2} v_T^2

=>           v_T = \sqrt{\frac{9.8 * 16}{0.5} }

             v_T = 17.7 \ m/s

From the question we are told that the actual velocity of Tarzan is

            v = 11 m/s

The kinetic energy at the the velocity is mathematically represented as

         KE_A = \frac{1}{2} m v^2

Substituting values

          KE_A = \frac{1}{2} (85) *   11^2

          KE_A =  5142.5 J          

The kinetic energy at v_T is  

       KE =  \frac{1}{2}  * 85 * 17.7^2

=>     KE =  13314.83\ J

Now the percentage loss of kinetic energy is mathematically evaluated as

       %-loss  = \frac{KE -  KE_A}{KE}  * 100

substituting values

             %-loss  = \frac{13314.83 -  5142.5}{13314.83}  * 100

                %-loss  = 61.4%

The mass of Tarzan does not affect the speed because looking at this equation

                gh = \frac{1}{2} v_T^2

We see that the velocity of Tarzan is not dependent on the mass of Tarzan

4 0
3 years ago
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