Answer:
The maximum speed of the mass is 1.67 m/s.
Explanation:
We have,
Mass of object is 34 g or 0.034 kg
Spring constant of the spring is 78.1 N/m
Amplitude attained by the object is 3.5 cm or 0.035 m
It is required to find the maximum speed of the object in this spring mass system. The maximum speed is given by :
Plugging all the values in above formula,
So, the maximum speed of the mass is 1.67 m/s.
As change is velocity is
<span>Δv=<span>10 m s<span>−1</span></span>−<span>2 m s<span>−1</span></span>=<span>8 m s<span>−1</span></span></span>
and time taken is 3 seconds so acceleration is
<span>acceleration=<span>change in velocitychange in time</span></span>
So
<span>a=<span><span>8 m s<span>−1</span></span>3 s</span>=<span>2.7 m s<span>−<span>2</span></span></span></span>
Answer:
294.524 m^3
Explanation:
The volume of a cylinder is given by the formula ...
V = πr^2h
For a radius of 2.5 m and a length of 15 m, the volume is ...
V = π(2.5 m)^2(15 m) = 93.75π m^3 ≈ 294.524 m^3
The volume is about 294.52 cubic meters.
Answer:
32%
Explanation:
For a heat engine, efficiency is work out divided by heat in:
η = Wₒ / Qᵢ
Since energy is balanced, heat in is the sum of work out and heat out:
Qᵢ = Wₒ + Qₒ
Therefore:
η = Wₒ / (Wₒ + Qₒ)
Given Wₒ = 710 J and Qₒ = 1480 J:
η = 710 / (710 + 1480)
η = 0.32
The thermal efficiency is 32%.
