A 117 kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 62.
1 answer:
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Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of
, and a mass of 
. So, the number of protons is
And so the total charge of these protons is
So, the neutralize this charge, we must have
electrons such that their total charge is
Since the charge of each electron is
, the number of electrons needed is
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is
, the total mass of electrons should be
Each proton has a charge of
So, the neutralize this charge, we must have
Since the charge of each electron is
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is
Answer:
a) t = 11.2 s
b) v = 70.5 mph
Explanation:
a)
- Since we need to find the time, we could use the definition of acceleration (rearranging terms) as follows:
- where vf = 50 mph, and v₀ = 10 mph.
- However, we still lack the value of a.
- Assuming that the acceleration is constant, we can use the following kinematic equation:
- Since we know that Δx = 500 ft, we could solve (2) for a.
- In order to simplify things, let's first to convert v₀ and vf from mph to m/s, as follows:
- We can do the same process with Δx, from ft to m, as follows:
- Replacing (3), (4), and (5) in (2) and solving for a, we get:
- Replacing (6) in (1) we finally get the value of the time t:
b)
- Since the acceleration is constant, as we know the displacement is another 500 ft (152.4m), if we replace in (2) v₀ by the vf we got in a), we can find the new value of vf, as follows:
- If we convert vf again to mph, we have: