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Triss [41]
3 years ago
9

Two conducting parallel plates 5.0 × 10−3 meter apart are charged with a 12-volt potential

Physics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer: 2.4×10^-3 v/m

Explanation: distance between plates of capacitor (d) =5.0×10^-3m

Potential difference between plates (v) = 12v

Force on electronic charge (f) = 3.8×10^-16 N

Strength of electric field (E) =?

The formulae that relates potential difference, eoectiic field strength and distance between plates is given as

v = Ed

By substituting the parameters, we have that

12 = E × 5.0×10^-3

E = 12/ 5.0 × 10^-3

E = 2.4×10^-3 v/m

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Mr. F has taken in a lot of fluid and put out very little. During this period his heart rate has increased a little and his bloo
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If a converging lens forms a real, inverted image 24.0 cm to the right of the lens when the object is placed 48.0 cm to the left
viva [34]

Answer:

Focal length, f = 16 cm

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2. A common physics experiment involves lowering an open tube into a cylinder of water and moving the tube up and down to adjust
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Answer:

Explanation:

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