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QveST [7]
3 years ago
6

please answer as soon as possible. How does the gravitational pull of different objects in space affect other objects in space?

Physics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

Every object in space exerts a gravitational pull on every other

explanation :  gravity influences the paths taken by everything traveling through space. It is the glue that holds together entire galaxies. It keeps planets in orbit. It can also cause life-destroying asteroids to crash into planets..

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A car's gas tank contains 58.7 kg
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Answer:

721 kg/m^3

Explanation:

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3 years ago
Radioactive isotopes are used to a. determine the absolute age of rocks. c. determine how rocks are formed. b. determine the rel
PolarNik [594]
Hello <span>Mr1guy24 

Question: </span><span>Radioactive isotopes are used to?

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4 years ago
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The first Lunar Olympics is to be held on the moon inside a huge dome. Of the usual Olympic events track, field, swimming, gymna
mars1129 [50]
I think track would be most affected.
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4 years ago
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

6 0
3 years ago
Gravitational potential energy is always calculated with
ss7ja [257]

Answer:

kinetic energy as it involves dispersal of energy

7 0
3 years ago
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