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3 years ago

Help pls-

Mathematics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

Answer 1: $6,289

Answer 2: $198

Step-by-step explanation:

a(10)=10,000(1+.05)^10

=16,288.95 =16,288-10,000=$6,289

A(t)=pe^rt=a(10)=10,000e^(.05)(10)=16,487-10,000=6487

6487-6289=$198

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Mrs Alivia’s bathroom is in the shape of a rectangle with a width of 6 feet. Her kitchen is in the shape of a rectangle with a w

Vedmedyk [2.9K]

Answer:

1. The length of the bathroom is equal to its width. FALSE

2. Equation 2(x+6)=29 can be used to find the length of the bathroom, x.

TRUE

3. The legend of the bathroom is 11.5 feet. FALSE

4. The equation 2 x+6=29 can be used to find the length of bathroom, x.

FALSE

5. The length of the bathroom is 8.5 feet. TRUE

Step-by-step explanation:

Here, given:

The width of the bathroom = 6 feet

The width of the kitchen = 10.75 ft

The perimeter of the bathroom = 29 feet

Let us assume the length of the bathroom = k units

PERIMETER OF A RECTANGLE = 2 ( LENGTH + WIDTH)

Now, for the Mrs Avila's bathroom

29 feet = 2 (k + 6)

⇒ 29 = 2k + 12

or, 2 k = 29 - 12 = 17

⇒ k = 17/2 = 8.5 feet

So, the length of the bathroom = 8.5 units

Now, let us consider the given statements:

1. The length of the bathroom is equal to its width. FALSE

As here, Length= 8.5 units and width = 6 units

2. Equation 2(x+6)=29 can be used to find the length of the bathroom, x.

TRUE

3. The legend of the bathroom is 11.5 feet.

FALSE, the length of the bathroom is 8.5 units.

4. The equation 2 x+6=29 can be used to find the length of bathroom, x.

FALSE, the correct equation that can be used is 2x + 12 = 29

5. The length of the bathroom is 8.5 feet.

TRUE

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Simora [160]

Answer:

$1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}$

Step-by-step explanation:

Taking the succession:

$1+r+r^{2}+r^{3}+.....+r^{n-1}$

You can multiply and divide by 1-r without chaging the result:

$\frac{1-r}{1-r} (1+r+r^{2}+r^{3}+.....+r^{n-1})$

Distributing the upper part of the fraction you have:

$\frac{1}{1-r} (1-r+r-r^{2}+r^{2}-r^{3}+r^{3}-r^{4}+.....+r^{n-1}-r^{n})$

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