Because if there's no force on the object, then it just moves in a straight line.
Answer:
24 N
Explanation:
Given,
Unstretched length or original length , x1 = 12cm
Stiffness constant, k = 8 N/cm
Load required to take spring to a length , x2 of 15cm
Recall the relation :
F = Ke
Where, e = extension
e = x2 - x1
e = (15 - 12) = 3
F = ke
F = 8 N/cm * 3cm
F = 24 N/cm*cm
F = 24 N
Hence, required load = 24 N
1) Let's call
the speed of the southbound boat, and
the speed of the eastbound boat, which is 3 mph faster than the southbound boat. We can write the law of motion for the two boats:
2) After a time
, the two boats are
apart. Using the laws of motion written at step 1, we can write the distance the two boats covered:
The two boats travelled in perpendicular directions. Therefore, we can imagine the distance between them (45 mi) being the hypotenuse of a triangle, of which
and
are the two sides. Therefore, we can use Pythagorean theorem and write:
Solving this, we find two solutions. Discarding the negative solution, we have
, which is the speed of the southbound boat.
Answer:
27.6 m/s
5.64 s
Explanation:
Given:
Δy = 39 m
a = -9.8 m/s²
v = 0 m/s
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (39 m)
v₀ = 27.6 m/s
Find: 2t
Δy = vt − ½ at²
(39 m) = (0 m/s) t − ½ (-9.8 m/s²) t²
t = 2.82 s
2t = 5.64 s
Answer:
200 K
Explanation:
0 °C = 273 K
-73°C = 273 K - 73 K = 200 K