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Lana71 [14]
3 years ago
11

David wants to experiment with the device, so he connects an ammeter into the circuit and measures 11.5 AA when the device is co

nnected to the car's battery. From this, he calculates the time to boil a cup of water using the device. If the energy required is 100 kJkJ , how long does it take to boil a cup of water?
Physics
1 answer:
Mandarinka [93]3 years ago
4 0

Answer:

2.42hours

Explanation:

To calculate the time taken to boil the cup of water, we will use the formula

Q = It where

Q is the total energy required to boil the water = 100KJ = 100,000Joules

I is the current = 11.5A

t is the time taken to boil the water

t = Q/I

t = 100,000/11.5

t = 8695.65seconds

t = 2.42hours

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An Astronomer who made a list of 100 nebulae and galaxies that could

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2 years ago
How do you identify the number of valence electrons in an element using periodic table
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You may look at what group they are in
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5 0
3 years ago
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Fiora starts riding her bike at 18 mi/h. After a while, she slows down to 12 mi/h, and maintains that speed for the rest of the
lord [1]

Answer:

t = 2.5 hours

Explanation:

given,

speed of the bike for t time= 18 mi/h

final speed of the bike after t time = 12 mi/h

total distance, D = 69 miles

total time, T= 4.5 hour

time for which speed of the bike is 18 mi/h = ?

we know distance = speed x time

now,

18 x t + 12 (4.5 - t) = 69

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4 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
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Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

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a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

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Answer:

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