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olga nikolaevna [1]

2 years ago

13

If a roller coaster has 50,000 J of potential energy at the top of the first hill, how much kinetic energy does it have at the l

owest point?

1 answer:

Fed [463]2 years ago

4 0

Answer:

50,000 J because of the transformation of energy

Explanation:

You might be interested in

A stone of mass 0.2 kg falls with an acceleration of 10.0 m/s. How big is the force that causes this acceleration?

Kobotan [32]

Answer:

$\boxed {\boxed {\sf 2 \ Newtons}}$

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= m \times a$

The mass of the stone is 0.2 kilograms and the acceleration is 10.0 meters per square second.

m= 0.2 kg
a= 10.0 m/s²

Substitute the values into the formula.

$F= 0.2 \ kg * 10.0 \ m/s^2$

Multiply.

$F=2 \ kg*m/s^2$

Convert the units.

1 kilogram meter per square second (kg*m/s²) is equal to 1 Newton (N)
Our answer of 2 kg*m/s² is equal to 2 N

$F= 2 \ N$

The force is <u>2 Newtons.</u>

4 0

2 years ago

Two charges, X and Y, are placed along the x-axis. Charge X is +18 nC and is placed at x = 0. Charge Y is placed at a location o

Helen [10]

Answer:

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m.

Explanation:

The Coulomb force between two charges, $Q_1$ and $Q_2$ , separated by a distance, $d$ , is given

$F = k\dfrac{Q_1Q_2}{r^2}$

<em>k</em> is a constant.

For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.

It is to be placed along the <em>x</em>-axis. Hence, it is on the same line as charges X and Y.

Let the charge on Z be <em>Q</em>. It is positive.

Let the distance from charge X be <em>x m.</em> Then the distance from charge Y will be (0.60 - <em>x</em>) m.

Force due to charge X

$F_X = k\dfrac{18Q}{x^2}$

Force due to charge Y

$F_Y = k\dfrac{-27Q}{(0.60-x)^2}$

Since both forces are equal and opposite,

$F_X = -F_Y$

$k\dfrac{18Q}{x^2} = -k\dfrac{-27Q}{(0.60-x)^2}$

$\dfrac{2}{x^2} = \dfrac{3}{(0.60-x)^2}$

$2(0.60-x)^2 = 3x^2$

$2(0.36-1.20x+x^2) = 3x^2$

$0.72-2.40x+2x^2 = 3x^2$

$x^2+2.40x-0.72 = 0$

Applying the quadratic formula,

$x = \dfrac{-2.40\pm\sqrt{2.40^2 - (4)(1)(-0.72)}}{2} = \dfrac{-2.40\pm\sqrt{8.64}}{2}$

$x = -2.7$ or $x = 0.27$

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m

3 0

3 years ago

Given a force of 100 N and an acceleration of 10 m/s^2, what is the mass?

frutty [35]

Given:

Force(F): 100 N

Acceleration: 10 m/s^2

Now we know that

F= mx a

Where F is the force acting on the object which is measured in Newton

m is the mass of the object measured in Kg

a is the acceleration measured in m/s^2

Substituting the given values in the above formula we get

100= 10m

m= 10 Kg

6 0

3 years ago

Read 2 more answers

Definition of Newton’s first law of motion

kipiarov [429]

Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

3 0

2 years ago

Read 2 more answers

A wave completes one vibration as it moves a distance of 2 meters at a speed of 20 meters per second. What is the frequency of t

Gemiola [76]

Answer:

I put the answer

Explanation:

Can you see it

6 0

2 years ago