1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga nikolaevna [1]
3 years ago
13

If a roller coaster has 50,000 J of potential energy at the top of the first hill, how much kinetic energy does it have at the l

owest point?
Physics
1 answer:
Fed [463]3 years ago
4 0

Answer:

50,000 J because of the transformation of energy

Explanation:

You might be interested in
Calculate the acceleration of a train travelling from rest to 24 m/s in 12 seconds.
Vilka [71]
Answer: A 2m/s^2

Steps: Formula for acceleration. (Velocity Final - Initial Velocity) / Time

(24 - 0) / 12 = 2
3 0
3 years ago
Pls help pls due today
BaLLatris [955]
The mutualism I believe. So sorry if I’m wrong
7 0
3 years ago
Read 2 more answers
Two everyday examples of a starting motion
Tasya [4]
Pushing, pulling is the answer
8 0
3 years ago
The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

=9.8(1 - 6400000/17696)

=9.8(1 − 0.00276)

9.8×0.99724

=9.773m/s^2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2

-----------------------------------------------------------------------

hope this helps :)

3 0
3 years ago
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel d
Dmitry [639]

Answer:

the distance in meters traveled by a point outside the rim is 157.1 m

Explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

\theta = \omega t\\\\\theta = (100 \frac{rev}{\min}  \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi  \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m

Therefore, the distance in meters traveled by a point outside the rim is 157.1 m

6 0
3 years ago
Other questions:
  • 4. Inflection best relates to A. vocabulary. B. volume. C. tone. D. pace.
    12·1 answer
  • A hot air balloon is flying above Grovenburg. To the left side of the balloon, the balloonist measure the angle of depression to
    8·1 answer
  • 8. A student does 1,000 J of work when she moves to her dormitory. Her internal energy is decreased by 3,000 J. Determine the he
    12·1 answer
  • Who created a steel plow
    12·2 answers
  • What evidence supported the Oscillating Big Bang?
    14·1 answer
  • If a bicyclist has a mass of 70 KG and a velocity of 25M/S, what is the momentum of the bicyclist?
    5·1 answer
  • What are newtons laws?
    11·1 answer
  • Forces between objects act when the objects are in direct contact or when they are not touching. Can you think of any forces tha
    9·2 answers
  • I need help and I don't understand if you can help me but let it be before 6:00
    5·1 answer
  • A scientist uses a camera to study the stars.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!