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insens350 [35]
4 years ago
9

Forces between objects act when the objects are in direct contact or when they are not touching. Can you think of any forces tha

t can act at a distance?
Physics
2 answers:
Tju [1.3M]4 years ago
7 0

Answer:

gravity

Explanation:

Gravity as well as electrostatic and magnetic attraction and repulsion provide real life examples of forces being exerted by one object on another without them being in contact with each other. Many children are aware of magnetism and have played with fridge magnets.

ss7ja [257]4 years ago
4 0

Answer:

Magnetic, electric, and gravitational forces can be exerted, even though the objects involved do not touch each other.

Explanation:

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What is the effect on the force of gravity between two objects if the mass of one object remains unchanged while the distance to
drek231 [11]

Answer:

The force of gravity after you double the mass and the distance is half of the initial force: F_{2}=\frac{1}{2}F_{1}

Explanation:

The initial force of gravity is:

F_{1}=\frac{Gm_{1}m_{2}}{r^2}

where G is the universal gravitational constant, m_{1} is the mass of the first object, m_{2} is the mass of the second object, and r is the distance between the objects.

If the mass of the second object is doubled, now we have 2m_{2}, and if the distance between the objects is also doubled instead of r now we have 2r.

So the force of gravity now is:

F_{2}=\frac{Gm_{1}(2m_{2})}{(2r)^2}\\ F_{2}=\frac{2Gm_{1}m_{2}}{4r^2} \\F_{2}=\frac{1}{2} \frac{Gm_{1}m_{2}}{r^2}

and we know that F_{1}=\frac{Gm_{1}m_{2}}{r^2}

so the new force of gravity is:

F_{2}=\frac{1}{2}F_{1}

The force of gravity after you double the mass and the distance is half of the initial force.

3 0
3 years ago
a) One of the moons of Jupiter, named Io, has an orbital radius of 4.22 108 m and a period of 1.77 days. Assuming the orbit is c
hoa [83]

Answer:

According to Kepler's 3rd law.

It states that the orbital period, T is related to the distance, r as:

T² =  4 π²r³ /G  M

where G is the universal gravitational constant  =  6.673 × 10⁻¹¹ Nm²/kg²

Rearranging for M should give Jupiter's mass.

M =   4 π²r³/GT²

T= 1.77 days × 24 h/day × 60 min/h × 60 s/min = 1.53 × 10⁵ s

r = 4.22x10⁸ m

M = 4π² ((4.22 × 10⁸ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (1.53 × 10⁵ s)²)

M = 1.90 × 10²⁷kg

The mass of Jupiter is 1.90 × 10²⁷kg.

1.90 × 10²⁷kg

T= 7.16 days × 24 h/day × 60 min/h × 60 s/min = 6.19 × 10⁵s

r = 1.07x10⁹ m

M = 4π² ((1.07 × 10⁹ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (6.19 × 10⁵ s)²)

M = 1.90 × 10¹⁷kg

The mass of Jupiter is 1.90 × 10¹⁷kg.

THE RESULTS TO PART A and B ARE NOT CONSISTENT. The reason is because of the difference in radius of each satellites from Jupiter. i.e the farther away the moons, the smaller they become in space and the more the number of days to complete an orbit.

8 0
3 years ago
A fire warms you by transferring _<br> energy
NemiM [27]
Answer- thermal energy :)
8 0
4 years ago
Read 2 more answers
The design of a 60.0 cm industrial turntable requires that it has a kinetic energy of 0.250 j when turning at 45.0 rpm. What mus
Aneli [31]

Answer:

The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Explanation:

Given;

radius of the turnable, r = 60 cm = 0.6 m

rotational kinetic energy, E = 0.25 J

angular speed of the turnable, ω = 45 rpm

The rotational kinetic energy is given as;

E_{rot} = \frac{1}{2} I \omega ^2

where;

I is the moment of inertia about the axis of rotation

ω is the angular speed in rad/s

\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s

E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2

Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

5 0
3 years ago
In a physics experiment, a ball is released from rest, and it falls toward the ground. The timer was not paying attention but es
tigry1 [53]

Answer:

(A) –14m/s

(B) –42.0m

Explanation:

The complete solution can be found in the attachment below.

This involves the knowledge of motion under the action of gravity.

Check below for the full solution to the problem.

4 0
4 years ago
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