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3 years ago

The figure below depicts a triangle formed by the labeled

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

8 0

The answer is O 27 lol

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(a) It takes 40 pounds of seed to completely plant a 6-acre field. How many pounds of seed are needed per acre? poundsperacre

lakkis [162]

Answer: 6 2/3 or 6.67 pounds per acre (depending on how you write it)

Step-by-step explanation:

40 pounds/ 6 acres

= 6 2/3 or 6.67 pounds per acre

6 0

3 years ago

How many hours would someone who earns $6.25 per hour have to work to earn $225.65?

AURORKA [14]

6.25x = 225.65
x = 225.65 / 6.25
x = 36.104....so u would basically have to work 37 hrs

3 0

3 years ago

Read 2 more answers

I need help please!!

inna [77]

Y=-2x+5 that is your function

6 0

3 years ago

Read 2 more answers

Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).

AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

$M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Given:

J = (-2, 2)
L = (4, 0)

$\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)$

Given:

M = (3, 7)
K = (-1, -5)

$\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)$

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare. If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

$\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}$

Given:

J = (-2, 2)
L = (4, 0)

$\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13$

Given:

M = (3, 7)
K = (-1, -5)

$\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3$

$\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1$

Hence segments JL and MK are perpendicular

4 0

2 years ago

Please help! Find the x intercept and the y intercept of the graph of the equation

soldi70 [24.7K]

Answer:

5y=10-2x

y=(10-2x)/5

2x=10-5y

X=(10-5y)/2

4 0

3 years ago