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Veronika [31]
3 years ago
8

Given the formula of a compound: (1) aldehyde (2) alkene (3) alkyne (4) alcohol

Chemistry
2 answers:
Nataly [62]3 years ago
5 0

Answer:

Number 3 alkyne is the answer

Explanation:

sweet-ann [11.9K]3 years ago
3 0

Answer: The answer is Alkyne.

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What is the molarity of a solution that contains 2.93 g of NaCl dissolved in 0.025 L? 0.0012 M 0.050 M 1.3 M 2.0 M​
MakcuM [25]

Answer:

2.0 M

Explanation:

Step 1: Given data

  • Mass of NaCl (solute): 2.93 g
  • Volume of the solution: 0.025 L

Step 2: Calculate the moles corresponding to 2.93 g of NaCl

The molar mass of NaCl is 58.44 g/mol.

2.93 g × 1 mol/58.44 g = 0.0501 mol

Step 3: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.0501 mol/0.025 L = 2.0 M

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3 years ago
The density of pure gold (Au) is 19.3 g/cm3. What is the mass of a block of gold that measures 1.2 cm x 4.00 cm x 3.20 cm? Pleas
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Answer:

296.448 g

Explanation:

Density:

we know that density of an object can be measured by dividing its mass to its volume.

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m= mass

V= volume

Given data:

volume= 1.2 cm x 4.00 cm x 3.20 cm =15.36 cm3

density=  19.3 g/cm3

mass=?

Now we will put the values in the formula,

d=m/v

d x V= m

m = 15.36 cm3 x 19.3 g/cm3

m=296.448 g

so the mass of block of gold is 296.448 g

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