As the first five elements in Group 14 are considered in order from top to bottom, there are changes in both the
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The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
<h3>What is current?</h3>The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:
There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:
The mass of Ni to be deposited is 1.22 grams. The charge required is given as:
The current required to transfer 4010.7 C of charge in 1800 seconds is given as:
Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
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Answer: Theoretical yield is 313.6 g and the percent yield is, 91.8%
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 3 moles of
Thus 2.8 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of give = 2 moles of
Thus 2.8 moles of give =
of
Mass of
Theoretical yield of liquid iron = 313.6 g
Experimental yield = 288 g
Now we have to calculate the percent yield
Therefore, the percent yield is, 91.8%