The volume of CO₂ at STP = 2.8 L
<h3>Further explanation</h3>
Given
21 gram of sodium hydrogen carbonate-NaHCO₃
Required
Volume of CO₂
Solution
The decomposition of sodium bicarbonate into sodium carbonate, carbon dioxide, and water :
<em>
2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)</em>
mol of NaHCO₃ :
= mass : MW NaHCO₃
= 21 g : 84 g/mol
= 0.25
From the equation, mol ratio of NaHCO₃(s) :CO₂(g) = 2 : 1, so mol CO₂ :
= 1/2 x mol NaHCO₃
= 1/2 x 0.25
= 0.125
At STP, 1 mol gas = 22.4 L, so for 0.125 mol :
= 0.125 x 22.4 L
= 2.8 L
To find the temperature in the problem, we apply the ideal gas law, PV=nRT where R=8.314 Pam3/mol K. Substituting the given, T= 153,000 Pa*1.5x10^-4 m3/ [(0.75 mol)(<span>8.314 Pam3/mol K)]. The temperature is equal to 3.68 kelvin. </span>
Answer:
The number of energy levels increases as you move down a group as the number of electrons increases.
Explanation:
Each subsequent energy level is further from the nucleus than the last. Therefore, the atomic radius increases as the group and energy levels increase. 2) As you move across a period, atomic radius decreases.
Answer:
Boyle's law, which describes the inversely proportional relationship between the absolute pressure and volume of a gas, if the temperature is kept constant within a closed system. Among his works, The Sceptical Chymist is seen as a cornerstone book in the field of chemistry.
Answer:
D
Explanation:
The formula to find the density of an object is mass/volume. You know the mass in this problem is 112.8 grams, and the volume is 63 cm^3. Now you can plug this information into the density formula as 112.8/63, which is about 1.8. Now you just add the cm^3/g and you have your answer.
