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Talja [164]
3 years ago
5

Calculate the mass in grams, in 2.28 mol of H2SO4. Please show your work to receive credit.

Chemistry
1 answer:
solmaris [256]3 years ago
4 0

Answer:

98g

Explanation:

h=1*2=2

s=32

0=16*4=64

64+32+2=98

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What is an example of kinetic energy at work,1 a ball lodge in the tree, 1 a frisbee flaying in the air, 3 a car in the garage
AfilCa [17]

Answer:

a frisbee flaying in the air

Explanation:

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where;

  • K.E represents kinetic energy measured in Joules.
  • M represents mass measured in kilograms.
  • V represents velocity measured in metres per seconds square.

Hence, an example of kinetic energy at work is a frisbee flaying in the air because it would possess energy due to its motion in the air.

8 0
3 years ago
Rolls of foil are 300mm wide and 2.020mm thick. (The density of foil is 2.7 g/cm^3). What maximum length of foil can be made fro
horrorfan [7]

Answer:  8556 mm, or 855.6 cm (8560 mm to 3 sig figs)

Explanation:  Convert mm to cm by dividing by 10 (1cm/10mm)

Find the area of the foil face in cm^2 (30cm*0.2020cm) = 0.606 cm^2

Calculate the volume occupied by 1.40 kg of foil in cm^3.  1.40kg = 1400g

1.400g/(2.7 g/cm^3) = 518.5 cm^3 for 1.40 kg Au

   Volume = Area (of the face) * Length  

We want Length:

Length = Volume/Area

L = (518.5 cm^3/0.606 cm^2)

L = 855.6 cm (8556 mm)  Round to 3 sig figs (856 cm and 8560 mm)

5 0
3 years ago
If you want 1,775 mL of 48 M MgCl2 solution, how many grams of MgCl2 do you need?
vlada-n [284]

Answer:

0.1

Explanation:

3 0
3 years ago
In a step-down transformer, which side has more wire loops?
Marat540 [252]
B. The Secondary side of the step down transformer.
7 0
3 years ago
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What volume of air at 25°C and 1.00 atm can he stored in a 10.0 L high-pressure air tank if compressed to 25°C and 175 atm?
DaniilM [7]

Answer:

1750L

Explanation:

Given

Initial Temperature = 25°C

Initial Pressure = 175 atm

Initial Volume = 10.0L

Final Temperature = 25°C

Final Pressure = 1 atm

Final Volume = ?

This question is an illustration of ideal gas law.

From the given parameters, the initial temperature and final temperature are the same; this implies that the system has a constant temperature.

As such, we'll make use of Boyle's Law to solve this;

Boyle's Law States that:

P₁V₁ = P₂V₂

Where P₁ and P₂ represent Initial and Final Pressure, respectively

While V₁ and V₂ represent Initial and final volume

The equation becomes

175 atm * 10L = 1 atm * V₂

1750 atm L = 1 atm * V₂

1750 L = V₂

Hence, the final volume that can be stored is 1750L

5 0
3 years ago
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