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Dmitry [639]
3 years ago
14

How does the atmosphere help to make Earth livable? Check all that apply.

Chemistry
2 answers:
elena55 [62]3 years ago
7 0

Answer: Contains oxygen, provides warmth, blocks harmful energy from the Sun

Explanation:

it they main important to live on earth

Likurg_2 [28]3 years ago
5 0

Answer:

- contains oxygen

- provides warmth

- blocks harmful energy from the Sun

Explanation:

The atmosphere is crucial when it comes to providing living conditions on Earth. The gases in the atmosphere manage to balance the things just about right, so that the life can thrive. The atmosphere has oxygen, the gas that is used by pretty much every organism to be able to function. With its greenhouse gases, the atmosphere manages to trap the heat inside, thus providing warmth to the Earth. The numerous layers of the atmosphere manage to block in big portion the harmful energy from the Sun, with a special accent on the ozone layer, a layer that manages to stop most of the UV radiation.

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Write balanced chemical equations for the two ionization steps of sulfuric acid
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Hello!

Sulfuric acid (H₂SO₄) is a strong diprotic acid. "Diprotic" means that the acid donates 2 protons when dissociating in water to form ions. This happens in a series of two steps which are described below. The first reaction is basically a complete reaction while the second one is an equilibrium:

H₂SO₄(aq) + H₂O(l) → HSO₄⁻(aq) + H₃O⁺(aq)

HSO₄⁻(aq) + H₂O(l) ⇄ SO₄⁻²(aq) + H₃O⁺(aq)

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4 years ago
A chemistry student needs 60.00 g of butanoic acid for an experiment. He has available 120. g of a 36.9% w/w solution of butanoi
Finger [1]

Answer:

No solution

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(120.0 g solution)(36.9 g butanoic acid / 100 g solution) = 44.3 g butanoic acid.

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Below is a proposed mechanism for the decomposition of H2O2. H2O2 + I– → H2O + IO– slow H2O2 + IO– → H2O + O2 + I– fast Which of
Savatey [412]

Answer: Option (d) is the correct answer.

Explanation:

The given equations as as follows.

       H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}           (slow)

       H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + O_{2} + I^{-}

Therefore, overall reaction equation will be as follows.

     2H_{2}O_{2} + I^{-} + IO^{-} \rightarrow 2H_{2}O + O_{2} + IO^{-} + I^{-}

So, cancelling the spectator ions then the equation will be as follows.

         H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

        H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}

                 Rate law = k[H_{2}O_{2}][I^{-}]

Hence, the reaction is first order with respect to [I^{-}] and it is also first order reaction with respect to [H_{2}O_{2}].

Also, [I^{-}] acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is IO^{-} is a catalyst.

6 0
3 years ago
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