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Inessa [10]
2 years ago
14

N the ionic compound aluminum selenide, each atom of aluminum (gains or loses)

Chemistry
1 answer:
Volgvan2 years ago
6 0

Answer:

loses, gains

Explanation:

In the ionic compound aluminum selenide, each atom of aluminum will lose electrons while each atom of selenium will gain the electrons.

An ionic compound is an interatomic bond formed between a metal and non-metal. The metal is less electronegative compared to the non-metal. In this case, the metal will lose electrons to become positively charged whereas the non-metal, selenium will gain the electron to become negatively charged.

The electrostatic attraction between these oppositely charged ions leads to the formation of the ionic bond.

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For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
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<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

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