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alexira [117]
3 years ago
14

If 4/3 x 3/4 = 5k, then k = ?​

Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

k= 1 /15 x^3

Step-by-step explanation:

4/3 x 3/4 = 5k

5k= 1 /3 x^3

k= 1 /15 x^3

Tpy6a [65]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

4/3 times 3/4 is one, so k is 1/5

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Answer:

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

Step-by-step explanation:

Sets are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Lots of 50 means that N = 50

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P(X = 2) = h(2,50,4,5) = \frac{C_{5,2}*C_{45,2}}{C_{50,4}} = 0.0430

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

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