The temperature is held constant at (b) and (d). At these points, the substance is changing states. B is changing from solid to liquid and D is changing from liquid to gas
Answer:
New temperature T2 = -124.7 °C
Explanation:
Given:
Old volume V1 = 135 cm³
New volume V2 = 140 cm³3
Old temperature T1 = 143 K
Find:
New temperature T2
Computation:
V1 / T1 = V2 / T2
135 / 143 = 140 / T2
New temperature T2 = 148.3 K
New temperature T2 = 148.3 - 273
New temperature T2 = -124.7 °C
Answer:
can you please list the options it gives u
The reaction s that are redox reactions are
4Li(s) +O2 (g)→ 2Li2O (s)\
Mg(s) + Fe2+ (aq)→ Mg2+(aq) + Fe(s)
<h3>Explanation</h3>
A redox reaction involve both oxidation and reduction. During redox reaction there is change in oxidation states. For example in
4Li +O2 →2Li2O Li is oxidized while O is reduced
in Mg +Fe2+ → Mg2+ +Fe Mg is oxidized since it move from oxidation state 0 to 2+ while Fe2+ is reduced since it move from oxidation state of 2+ to 0
The ionization constant equation is:
=1.0 × 
at 25°C
the option is 1.
Explanation:
Sometimes in pure water one proton of the water molecule(hydrogen ion) will get attracted to the lone pairs present in another water molecule.This causes the hydrogen ion to leave the present water(leaving the 
behind) molecule ad gets attached to another water molecule leading to the formation of the hydronium ion(
,hydronium ion).
This process is called auto-ionization of water because the water molecule ionizes into 
and ions.
<h2>
<u>
+</u>
<u>
→</u>
<u>
+ </u>
</h2>
As such the equilibrium constant,which is measure of concentration of products to concentration of reactants,will be very slow.
∴the ionization constant of water at 25°C is 1.0 × .
(i.e.)option<u> c</u> is correct answer []=[]
