<u>Answer:</u> The correct option is D) 
<u>Explanation:</u>
The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.
A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.
For the given chemical reaction:
<u>On the reactant side:</u>
Oxidation number of Zn = 0
Oxidation number of Ag = +1
<u>On the product side:</u>
Oxidation number of Zn = +2
Oxidation number of Ag = 0
As the oxidation number of Ag is decreasing from +1 to 0. Thus, is getting reduced.
Hence, the correct option is D)
The pH of the solution of the given acid is 3.099
Let HX be the weak acid:
HX ⇌ 
+ 
For which:
= [ ][ ] / [HX]
If lies in the range 
we can assume that the equilibrium concentrations used in the expression are a good enough approximation to the initial concentrations.
Rearranging and taking negative logs of both sides gives:
pH = ![\frac{1}{2} [pK_{a} - loga]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5BpK_%7Ba%7D%20-%20loga%5D)
a is the concentration of the acid.
= -log (2×
) = 5.69
pH = ![\frac{1}{2} [5.69- (-0.508)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5B5.69-%20%28-0.508%29%5D)
pH = 3.099
Learn more about pH of acid here;
brainly.com/question/13043236
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Fossils can not be formed in igneous rock because before it cooled from the liquid magma state, any renants of fossils would be destroyed and melted... they form in sedimentary because thats where they can be buried and perserved the easiest, metamorphic would destroy them from the pressures and temperatures involved in there formations
I have to see the simulation
Answer:
7.43 × 10²⁴ m⁻³
Explanation:
Data provided in the question:
Conductivity of a semiconductor specimen, σ = 2.8 × 10⁴ (Ω-m)⁻¹
Electron concentration, n = 2.9 × 10²² m⁻³
Electron mobility, 
= 0.14 m²/V-s
Hole mobility, 
= 0.023 m²/V-s
Now,
σ = 
or
σ = 
here,
q is the charge on electron = 1.6 × 10⁻¹⁹ C
p is the hole density
thus,
2.8 × 10⁴ = 1.6 × 10⁻¹⁹( 2.9 × 10²² × 0.14 + p × 0.023 )
or
1.75 × 10²³ = 0.406 × 10²² + 0.023p
or
17.094 × 10²² = 0.023p
or
p = 743.217 × 10²²
or
p = 7.43 × 10²⁴ m⁻³
