Find the measure of the arc or angle indicated.

Katarina makes 2 gallons of punch for her party how many cups of punch did she make

Oduvanchick [21]

Answer:

38

Step-by-step explanation:

7 0

3 years ago

0.8b= -1.12 what is b

Sunny_sXe [5.5K]

B=-1.4 because -1.4•.8=-1.12

6 0

4 years ago

You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week

aliya0001 [1]

Answer:

$q = -6p + 104$

Step-by-step explanation:

Linear function:

A linear function has the following format:

$q = mp + b$

In which m is the slope and b is the q-intercept.

One week you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night.

This means that we have these following points: (4,80), (10,44).

Finding the slope:

With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

Change in p: 10 - 4 = 6

Slope: $m = \frac{-36}{6} = -6$

So

$q = -6p + b$

Finding b:

We replace one of the points. Replacing (4,80).

$q = -6p + b$

$80 = -6*4 + b$

$b = 104$

So

$q = -6p + 104$

7 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

4 years ago

After reading the story “First Day of School,” pick up where the story left off and add a climax, falling action and resolution.

Anit [1.1K]

Although this question asks for original work, and therefore, only you can complete it, we can provide an example to help you guide your work:

"My sister and I said goodbye to mom, and we were ready to finally approach the school and begin one of the most important days of our lives. We were nervous, and worried about whether this year was going to be a good one. I turned around to my sister and asked:

- Are you ready?

- I'm so not ready...

We approached the school, and as we pulled the door, the most delicious smell hit us. It smelled like sweetness, and like a day in the park. We walked in, and what we saw left us in awe.

The school had organized a festival! In order to make the first day of school easier, the morning classes had been cancelled, and we were instead allowed to run and play for a few hours, in order to get to know each other. I saw donuts, corndogs and ice cream. I also saw many kids running around. My sister could not believe her eyes.

- This is the best day ever! - she yelled, while she ran to grab a donut."

In this addition, the conflict is an internal one, as the children feel worried about school. However, this is resolved by the festival that was organized. The climax occurs when the children notice the festival, while the falling action and resolution occur when the children are able to relax and their worries about school disappear.

8 0

3 years ago