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3 years ago

Static energy is an enemy and a friend both. Give reason

Physics

2 answers:

ExtremeBDS [4]3 years ago

8 0

Answer:

In their personal lives, most people regard energy as an essential friend. It powers our computers, warms our homes in the winter, fuels our cars and planes, and provides a necessary input to produce virtually everything we use. Modern life would be inconceivable without the friendly side of energy.

But in recent decades, energy has also become an enemy. Presidents have lamented our “addiction to oil,” we have gone to war to protect oil fields from hostile powers, and air pollution from fossil fuels kills tens of thousands of people every year. Perhaps most worrisome, the accumulation of greenhouse gases such as carbon dioxide threatens to change the earth’s climate in ways that are unpredictable and potentially dangerous.

The two faces of energy are the primary reason why energy policy is so controversial and tangled. We need national policies that address the enemies of pollution and global warming. But because energy is such a large part of consumer budgets and so central to our advanced economies, people are reluctant to allow energy prices to reflect the true social costs of energy consumption. We see this tradeoff play out in energy and environmental policy year in and year out.

Explanation:

bonufazy [111]3 years ago

6 0

oAnswer: because i can hurt you and i would say its funny and cool

Explanation:

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sergeinik [125]

Answer:

1. geothermal

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4 0

3 years ago

Read 2 more answers

. A driver travels 4.25 km. in two minutes. If the driver’s initial velocity is 20m/s, what is the acceleration?

Novosadov [1.4K]

Answer:

32.9166667 m / s^2

Explanation:

s = 4.25km (1000m / 1km)

= 4250m

u = 20m/s

delta T = 20min (60sec / 1min)

= 1200s

Use formula s = ut + (1/2)at^2

4250m = 20m/s * 1200s + (1/2)a*1200s^2

Rearrange it to find a

a = (s-ut) / (1/2 * t^2)

a = (4250m - 20m/s*1200s) / (1/2 * 1200s^2)

a = -32.9166667 m / s^2

4 0

3 years ago

Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water. If the cylinder

jonny [76]

Answer:

0.10839 m

Explanation:

$P_1$ = Atmospheric pressure = 1 atm = 101325 Pa

$P$ = Total pressure at bottom of mecury = 1.2 atm

g = Acceleration due to gravity = 9.81 m/s²

h = d = Depth of mercury

$\rho_m$ = Density of mercury = $1.36\times 10^4\ kg/m^3$

$\rho_w$ = Density of water = $1000\ kg/m^3$

Pressure at the bottom is of the cylinder is given by

$P_2=P_1+\rho_wgh\\\Rightarrow P_2=101325+1000\times 9.81(0.7-d)$

Pressure at the bottom of mercury is

$P=P_2+\rho_mgh\\\Rightarrow 1.2\times 101325=101325+1000\times 9.81(0.7-d)+1.36\times 10^4\times 9.81\times d\\\Rightarrow 1.2\times 101325=123606d+108192\\\Rightarrow d=\dfrac{1.2\times 101325-108192}{123606}\\\Rightarrow d=0.10839\ m$

The depth of the mercury is 0.10839 m

7 0

4 years ago

A circular loop of wire lies in the plane of your screen. An increasing magnetic field (produced by another source) points out o

Rashid [163]

Answer:

clockwise direction

Explanation:

Direction of induced current is found with the help of Lenz's law . According to this law , the direction of induced current is such that it tries to neutralize or oppose the reason which creates this current .

In the given case , magnetic field is towards the viewer of the screen and it is increasing , so the induced current will have to create magnetic field in opposite to it . It means magnetic field will be created towards the screen into it . So the current will be induced in clockwise direction . This current will create magnetic field into the screen which will oppose increasing magnetic field out of screen .

7 0

3 years ago

A nonrelativistic electron is accelerated from rest through a potential difference. After acceleration the electron has a de Bro

aleksley [76]

Answer:

Potential difference though which the electron was accelerated is $2.67\times 10^{-6}\ uV\ .$

Explanation:

Given :

De Broglie wavelength , $\lambda=750\ nm.$

Plank's constant , $h=6.626\times 10^{-34}\ J.s \ .$

Charge of electron , $e=-1.6\times 10^{-19}\ C.$

Mass of electron , m=9.11\times 10^{-31}\ kg. $m=9.11\times 10^{-31}\ kg.$

We know , according to de broglie equation :

$\lambda=\dfrac{h}{mv}\\\\ v=\dfrac{h}{m\lambda}\\\\v=\dfrac{6.626\times 10^{-34}\ J.s \ }{9.11\times 10^{-31}\ kg\times 750\times 10^{-9}\ m }= 969.78\ m/s .$

Now , we know potential energy applied on electron will be equal to its kinetic energy .

Therefore ,

$qV=\dfrac{mv^2}{2}\\\\ V=\dfrac{mv^2}{2q}$

Putting all values in above equation we get ,

$V=2.67\times 10^{-6}\ uV .$

Hence , this is the required solution.

5 0

3 years ago