Hey there!

If the price per orange is $.26 and we want to know how many oranges he bought and we have our total, we can set o equal to how many oranges he got and set up an algebraic equation:

0.26o = 2.08

We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.

To isolate o, we divide both sides by .26 to get:

The answer is C- Jim bought 8 oranges.

Hope this helps!

4 0

2 years ago

Read 2 more answers

Square of (1\4A+1\4B)^2

miskamm [114]

Answer:4a = 2⋅(2a)⋅1 4 a = 2 ⋅ ( 2 a) ⋅ 1

Step-by-step explanation:

Factor 4a^2-4a+1. 4a2 − 4a + 1 4 a 2 - 4 a + 1. Rewrite 4a2 4 a 2 as (2a)2 ( 2 a) 2. (2a)2 − 4a+1 ( 2 a) 2 - 4 a + 1. Rewrite 1 1 as 12 1 2. (2a)2 − 4a+12 ( 2 a) 2 - 4 a + 1 2. Check that the middle term is two times the product of the numbers being squared in the first term and third term. 4a = 2⋅(2a)⋅1 4 a = 2 ⋅ ( 2 a) ⋅ 1.

7 0

2 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago