Answer:
mass of C₂H₄N₂ = 3.472 g
Explanation:
We have the following chemical reaction:
3 CH₄ + 5 CO₂ + 8 NH₃ → 4 C₂H₄N₂ + 10 H₂O
Using the masses given by the problem we calculate the number of moles for each reactant:
number of moles = mass / molecular weight
number of moles of CO₂ = 13.2 / 44 = 0.3 moles
number of moles of NH₃ = 2.18 / 17 = 0.13 moles
number of moles of CH₄ = 17 / 16 = 1.06 moles
We can see that the limiting reactant is ammonia NH₃. Now we can devise the following reasoning:
if 8 moles of NH₃ produces 4 moles of C₂H₄N₂
then 0.13 moles of NH₃ produces X moles of C₂H₄N₂
X = (0.13 × 4) / 8 = 0.062 moles of C₂H₄N₂
mass of C₂H₄N₂ = number of moles × molecular weight
mass of C₂H₄N₂ = 0.062 × 56 = 3.472 g
Answer:
D) Van der Waals
Explanation:
Given that the geometry is linear, one finds that the C = O bonds cancel out any polar effects due to the linear geometry ( O = C = O )and gives the molecule a net dipole of zero. Interactions are therefore dependent upon dispersion forces that are classified as Van der Waal Forces or London Forces.
For a Forty miles above the earth's surface, the temperature at 250k and the pressure at only 0.20 torr, the density of air at this altitude is mathematically given as
d=3.732*10{-4}g/l
<h3>What is the density of air at this altitude?</h3>
Generally, the equation for the ideal gas is mathematically given as
PV=(m/mw)RT
Therefore
d=m/v
d=26,664*20/83.14*250
d=0.37152
d=3.732*10{-4}g/l
In conclusion, the density
d=3.732*10{-4}g/l
Read more about Temperature
brainly.com/question/13439286
Answer:- 15.7 grams of NaCl can be formed.
Solution:- The balanced equation is:
From this balanced equation, there is 1:2 mol ratio between 
and 
.
Let's calculate the grams of NaCl for the given grams of both the reactants using stoichiometry and see which one gives least amount of it. The least amount of NaCl formed would be the answer to our problem.
The calculations are as follows:
= 16.1 g NaCl
= 15.7 g NaCl
From above calculations, sodium nitrate is limiting as it gives least amount of NaCl.
So, 15.7 grams of NaCl can be formed from given grams of the reactants.
Answer:
what are you writing btw??
