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alukav5142 [94]
4 years ago
9

Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a

great amount of angular momentum when rotating. A wind turbine has a total of 3 blades. Each blade has a mass of m = 5500 kg distributed uniformly along its length and extends a distance r = 46 m from the center of rotation. The turbine rotates with a frequency of f = 11 rpm.
Required:
a. Calculate the total moment of inertia of the wind turbine about its axis, in units of kilogram meters squared.
b. Calculate the angular momentum of the wind turbine, in units of kilogram meters squared per second.
Physics
1 answer:
Anton [14]4 years ago
4 0

Answer:

Explanation:

moment of inertia of each blade which is similar to rod rotating about its one end

= 1/3 ml²

moment of inertia of 3 blades = ml²

= 5500 x 46²

I = 11638 x 10³ kg m²

angular velocity = 2πn where n is rotation per second

n = 11 / 60

angular velocity = 2π x 11/60

= 1.1513 rad /s

angular momentum

= moment of inertia x angular velocity

=  11638 x 10³ x 1.1513

= 13399 x 10³ kg m² per second.

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Answer:

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7 + 5 = 12    

Explanation:

Since it asks for 2 vectors, you have to add 2 times.

8 0
3 years ago
A woman drives 6 miles, accelerating uniformly from rest to 70 mph. How long does it take for her to reach 70 mph?
Morgarella [4.7K]
Using the two kinematic equations that can be used for this problem are:
Vf = Vi + at and d=Vit +(1/2)*at^2
Since Vi (initial velocity) = 0 

The equations can further be simplified where a is the acceleration, t is the time, Vf is the final velocity which is 70 miles per hour and d is 6 miles

Vf = at
70 = at
a = 70/t---equation 1

d=(1/2)*a*(t^2)
6 = (1/2)*a*(t^2) ---equation 2

Substituting equation 1 to equation 2.
6= (1/2)*(70/t)*(t^2)
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t= 0.17142 hours or 10.28571 mins or 617.14 sec



6 0
3 years ago
John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
umka21 [38]

The horizontal component of the velocity is equal to: D. 15 m/s.

<u>Given the following data:</u>

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  • Angle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

V_x = Vcos(\theta)

Substituting the given parameters into the formula, we have;

\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5

Horizontal component, Vx = 15 m/s

Read more on horizontal component here: brainly.com/question/24681896

6 0
3 years ago
Average running speed is 8km/h. Convert this to m/s :
rosijanka [135]

Answer:

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Explanation:

Sorry if I'm wrong

6 0
3 years ago
Read 2 more answers
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user100 [1]

Answer:

Explanation:

I guess we are ASSUMING that this is a rear wheel drive car as a front wheel drive car will never get the front wheel normal force to zero

If we consider it as a statics problem and choose our moment center carefully...say 0.7 m above the rear wheel to ground contact point.

Call the traction force at the rear wheels F

The normal force on the front wheels will be zero, so no moment generated by the front wheels.

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