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Likurg_2 [28]
4 years ago
6

un resorte de 10cm de longitud recibe una magnitud de fuerza que lo estira hasta medir 15cm ¿cual es la magnitud de la tension u

nitaria o deformacion lineal? Si me explican la fórmula estaría genial!
Physics
1 answer:
Ber [7]4 years ago
8 0

Answer: 0.5

Explanation:

The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) \epsilon of a spring is given by the following formula:

\epsilon=\frac{\Delta L}{L}

Where:

L=10 cm  is the original length of the spring

\Delta L=L_{f}-L  is the elongation of the spring, being L_{f}=15 cm the length of the spring after a force is applied to it.

\epsilon=\frac{L_{f}-L}{L}=\frac{15 cm - 10 cm}{10 cm}

Then:

\epsilon=0.5

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