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4 years ago

6

un resorte de 10cm de longitud recibe una magnitud de fuerza que lo estira hasta medir 15cm ¿cual es la magnitud de la tension u

nitaria o deformacion lineal? Si me explican la fórmula estaría genial!

1 answer:

Ber [7]4 years ago

8 0

Answer: 0.5

Explanation:

The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) $\epsilon$ of a spring is given by the following formula:

$\epsilon=\frac{\Delta L}{L}$

Where:

$L=10 cm$ is the original length of the spring

$\Delta L=L_{f}-L$ is the elongation of the spring, being $L_{f}=15 cm$ the length of the spring after a force is applied to it.

$\epsilon=\frac{L_{f}-L}{L}=\frac{15 cm - 10 cm}{10 cm}$

Then:

$\epsilon=0.5$

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A)

In this part, we are told that the power if the engine is constant. The power of the engine is given by

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$P=\frac{\frac{1}{2}mv^2}{t}=const.$

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SInce power is constant, we can write:

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where:

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B)

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Learn more about accelerated motion:

brainly.com/question/9527152

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About power:

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#LearnwithBrainly

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