Answer:
Explanation:
In simplest terms, the fastest moving ones that are closest to the surface.
Answer:
Cyclothymic Disorder
Explanation:
Cyclothymic disorder is a rare type of mood disorder whose symptoms resemble that of bipolar disorder. Although, the symptoms are manifested in a milder manner when compared with those of bipolar disorder.
The mood shifts in cyclothymic disorder are not as extreme as with Bipolar disorder.
The normal moods in cyclothymic disorder can last for a longer time than in bipolar disorder.
Although, the mood swings in cyclothymic disorder are more frequent than in bipolar disorder.
The true causes of cyclothymic disorder are not specifically known but bipolar disorder & cyclothymic can both occur in the same family suggesting that they may share similar causes.
The density of the sphere is 0.0713 g/cm^3.
<h3>What is density? </h3><h3> </h3>
The density of a substance indicates how dense it is in a particular area. Mass per unit volume is the definition of a material's density. In essence, density is a measurement of how closely stuff is packed. It is a special physical characteristic of a certain thing.
The Greek scientist Archimedes made the discovery of the density principle. If you are familiar with the formula and the relevant units, calculating density is simple. The letter D can also be used to signify density instead of the symbol.
The circumference of the sphere = 32.5 mm
2 (pi) r
2 × 22/7 × r = 32.5
44/7 × r = 32.5
44 × r = 32.5 × 7
44 × r = 227.5
r = 227.5/44
r = 5.2
Now, V = (4/3) (pi) r^3
V = 4/3 × 22/7 × (5.2)^3
V = 4/3 × 22/7 × 140. 608
V = 589. 21 mm
V = 58.921 cm^3
Density = 4.20/58.92
D = 0.0713 g/cm^3
Therefore, the density is 0.0713 g/cm^3.
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First, since l = n-1,
5,4,-5,1/2 and 2,1,0,1/2 are the only answer choices left.
Next, since ml = -l to l,
2,1,0,1/2
is the answer because in 5,4,-5,1/2, the ml value of -5 is not in the range of -4 to 4, as notes by the value 4 for l.
Answer:
![\boxed{\sf Specific \ heat \ of \ the \ substance \ (c) = 0.85 \: J/g \degree C }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%20Specific%20%5C%20heat%20%20%5C%20of%20%5C%20the%20%5C%20substance%20%5C%20%28c%29%20%3D%20%20%20%200.85%20%5C%3A%20J%2Fg%20%20%20%5Cdegree%20C%20%7D%20)
Given:
Mass (m) = 10.0 g
Rise in temperature (∆T) = 8.58°C
Energy required (Q) = 73.2 J
To Find:
Specific heat of the substance (c)
Explanation:
Specific heat (c) of a substance is the energy required to raise the temperature of one gram of the substance by one degree Celsius.
Formula of specific heat is given as:
![\boxed{ \bold{c = \frac{Q}{m\Delta T}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7Bc%20%3D%20%5Cfrac%7BQ%7D%7Bm%5CDelta%20T%7D%7D%7D)
By substituting value of Q, m & ∆T in the formula we get:
![\sf \implies c = \frac{73.2}{10 \times 8.58} \\ \\ \sf \implies c = \frac{73.2}{85.8} \\ \\ \sf \implies c = 0.85 \: J/g \degree C](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20c%20%3D%20%20%20%5Cfrac%7B73.2%7D%7B10%20%5Ctimes%208.58%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Csf%20%5Cimplies%20c%20%3D%20%20%20%5Cfrac%7B73.2%7D%7B85.8%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Csf%20%5Cimplies%20c%20%3D%20%200.85%20%5C%3A%20J%2Fg%20%20%20%5Cdegree%20%20C%20)