Triangle ABC has vertices A( -3, 5) B ( 6, 9) and C ( -4, - 12) in the coordinate plane. The triangle is reflected over the x- a
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The linear equation is y = 4x - 4
And the graph of the linear equation can be seen in the image below.
<h3>How to graph the last line?</h3>
It seems that you already are good at graphing, so I will try to explain how to find the equation more in detail.
Remember that a general linear equation is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
In this case, we know that the y-intercept is -4, then b = -4, replacing that we get:
y = a*x - 4
Now we also can see that this line passes through the point (2, 4), this means that if we evaluate in x = 2, the outcome should be y = 4, replacing that we get:
4 = a*2 - 4
4 + 4 = a*2
8 = a*2
8/2 = a = 4
Then the slope is 4, and the linear equation is:
y = 4x - 4
The graph is below.
If you want to learn more about linear functions:
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